我需要在GROUP
条件的查询中拥有整行数。这是查询
SELECT COUNT(*) AS `numrows`
FROM (`exp_channel_titles`)
LEFT JOIN `exp_category_posts` cp ON `cp`.`entry_id`=`exp_channel_titles`.`entry_id`
LEFT JOIN `exp_categories` c ON `cp`.`cat_id`=`c`.`cat_id`
LEFT JOIN `exp_internships_placements` ip ON `ip`.`entry_id`=`exp_channel_titles`.`entry_id`
LEFT JOIN `exp_members` m ON `m`.`member_id`=`exp_channel_titles`.`author_id`
WHERE `exp_channel_titles`.`site_id` = '8'
AND `exp_channel_titles`.`channel_id` = '7'
AND (title like '%%')
GROUP BY `exp_channel_titles`.`entry_id`
和结果
numrows
3
2
1
1
1
1
1
1
1
1
1
1
我需要得到12.如果我删除GROUP
条件,我得到15个不正确的结果。你能告诉我如何让它按照我的需要工作吗?感谢。
答案 0 :(得分:2)
删除GROUP BY
,然后选择COUNT(DISTINCT exp_channel_titles.entry_id)
:
SELECT COUNT(DISTINCT `exp_channel_titles`.`entry_id`) AS `numrows`
FROM (`exp_channel_titles`)
LEFT JOIN `exp_category_posts` cp ON `cp`.`entry_id`=`exp_channel_titles`.`entry_id`
LEFT JOIN `exp_categories` c ON `cp`.`cat_id`=`c`.`cat_id`
LEFT JOIN `exp_internships_placements` ip ON `ip`.`entry_id`=`exp_channel_titles`.`entry_id`
LEFT JOIN `exp_members` m ON `m`.`member_id`=`exp_channel_titles`.`author_id`
WHERE `exp_channel_titles`.`site_id` = '8'
AND `exp_channel_titles`.`channel_id` = '7'
AND (title like '%%')