如何在Python中创建目录结构的zip存档？
答案 0 :(得分：689)
最简单的方法是使用shutil.make_archive。它支持zip和tar格式。
import shutil
shutil.make_archive(output_filename, 'zip', dir_name)
如果你需要做一些比压缩整个目录更复杂的事情（例如跳过某些文件），那么你需要像其他人建议的那样深入研究zipfile模块。
答案 1 :(得分：426)
正如其他人所指出的那样，你应该使用zipfile。文档告诉您哪些功能可用，但没有真正解释如何使用它们来压缩整个目录。我认为最简单的解释一些示例代码：
#!/usr/bin/env python
import os
import zipfile
def zipdir(path, ziph):
# ziph is zipfile handle
for root, dirs, files in os.walk(path):
for file in files:
ziph.write(os.path.join(root, file))
if __name__ == '__main__':
zipf = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED)
zipdir('tmp/', zipf)
zipf.close()
答案 2 :(得分：56)
将mydirectory的内容添加到新的zip文件中，包括所有文件和子目录：
import os
import zipfile
zf = zipfile.ZipFile("myzipfile.zip", "w")
for dirname, subdirs, files in os.walk("mydirectory"):
zf.write(dirname)
for filename in files:
zf.write(os.path.join(dirname, filename))
zf.close()
答案 3 :(得分：44)
如何在Python中创建目录结构的zip存档？
在Python 2.7+中，shutil具有make_archive函数。
from shutil import make_archive
make_archive(
'zipfile_name',
'zip', # the archive format - or tar, bztar, gztar
root_dir=None, # root for archive - current working dir if None
base_dir=None) # start archiving from here - cwd if None too
此处压缩的存档将命名为zipfile_name.zip。如果base_dir距离root_dir更远，则会排除base_dir以外的文件，但仍将父目录中的文件归档到root_dir。
我确实在使用2.7测试Cygwin上有一个问题 - 它想要一个root_dir参数，对于cwd：
make_archive('zipfile_name', 'zip', root_dir='.')
您也可以使用zipfile模块从shell执行此操作：
$ python -m zipfile -c zipname sourcedir
其中zipname是您想要的目标文件的名称（如果需要，添加.zip，它将不会自动执行），sourcedir是目录的路径。
如果您尝试使用__init__.py和__main__.py压缩python包，并且您不想要父目录，那么
$ python -m zipfile -c zipname sourcedir/*
和
$ python zipname
会运行包。 （请注意，您无法将子包作为压缩存档的入口点运行。）
如果您有python3.5 +，并且特别想要压缩Python包，请使用zipapp：
$ python -m zipapp myapp
$ python myapp.pyz
答案 4 :(得分：29)
此函数将递归压缩目录树，压缩文件，并在存档中记录正确的相对文件名。归档条目与zip -r output.zip source_dir生成的归档条目相同。
import os
import zipfile
def make_zipfile(output_filename, source_dir):
relroot = os.path.abspath(os.path.join(source_dir, os.pardir))
with zipfile.ZipFile(output_filename, "w", zipfile.ZIP_DEFLATED) as zip:
for root, dirs, files in os.walk(source_dir):
# add directory (needed for empty dirs)
zip.write(root, os.path.relpath(root, relroot))
for file in files:
filename = os.path.join(root, file)
if os.path.isfile(filename): # regular files only
arcname = os.path.join(os.path.relpath(root, relroot), file)
zip.write(filename, arcname)
答案 5 :(得分：15)
使用shutil，它是python标准库集的一部分。 使用shutil很简单（请参见下面的代码）：
代码：
import shutil
shutil.make_archive('/home/user/Desktop/Filename','zip','/home/username/Desktop/Directory')
答案 6 :(得分：11)
要将压缩添加到生成的zip文件中，请查看this link。
您需要更改：
zip = zipfile.ZipFile('Python.zip', 'w')
到
zip = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED)
答案 7 :(得分：5)
我对code given by Mark Byers做了一些更改。如果你有它们，下面的函数也会添加空目录。示例应该更清楚地说明添加到zip的路径是什么。
#!/usr/bin/env python
import os
import zipfile
def addDirToZip(zipHandle, path, basePath=""):
"""
Adding directory given by \a path to opened zip file \a zipHandle
@param basePath path that will be removed from \a path when adding to archive
Examples:
# add whole "dir" to "test.zip" (when you open "test.zip" you will see only "dir")
zipHandle = zipfile.ZipFile('test.zip', 'w')
addDirToZip(zipHandle, 'dir')
zipHandle.close()
# add contents of "dir" to "test.zip" (when you open "test.zip" you will see only it's contents)
zipHandle = zipfile.ZipFile('test.zip', 'w')
addDirToZip(zipHandle, 'dir', 'dir')
zipHandle.close()
# add contents of "dir/subdir" to "test.zip" (when you open "test.zip" you will see only contents of "subdir")
zipHandle = zipfile.ZipFile('test.zip', 'w')
addDirToZip(zipHandle, 'dir/subdir', 'dir/subdir')
zipHandle.close()
# add whole "dir/subdir" to "test.zip" (when you open "test.zip" you will see only "subdir")
zipHandle = zipfile.ZipFile('test.zip', 'w')
addDirToZip(zipHandle, 'dir/subdir', 'dir')
zipHandle.close()
# add whole "dir/subdir" with full path to "test.zip" (when you open "test.zip" you will see only "dir" and inside it only "subdir")
zipHandle = zipfile.ZipFile('test.zip', 'w')
addDirToZip(zipHandle, 'dir/subdir')
zipHandle.close()
# add whole "dir" and "otherDir" (with full path) to "test.zip" (when you open "test.zip" you will see only "dir" and "otherDir")
zipHandle = zipfile.ZipFile('test.zip', 'w')
addDirToZip(zipHandle, 'dir')
addDirToZip(zipHandle, 'otherDir')
zipHandle.close()
"""
basePath = basePath.rstrip("\\/") + ""
basePath = basePath.rstrip("\\/")
for root, dirs, files in os.walk(path):
# add dir itself (needed for empty dirs
zipHandle.write(os.path.join(root, "."))
# add files
for file in files:
filePath = os.path.join(root, file)
inZipPath = filePath.replace(basePath, "", 1).lstrip("\\/")
#print filePath + " , " + inZipPath
zipHandle.write(filePath, inZipPath)
上面是一个简单的函数，应该适用于简单的情况。你可以在我的Gist中找到更优雅的课程： https://gist.github.com/Eccenux/17526123107ca0ac28e6
答案 8 :(得分：2)
我有另一个可能有用的代码示例，使用python3，pathlib和zipfile。 它应该适用于任何操作系统。
from pathlib import Path
import zipfile
from datetime import datetime
DATE_FORMAT = '%y%m%d'
def date_str():
"""returns the today string year, month, day"""
return '{}'.format(datetime.now().strftime(DATE_FORMAT))
def zip_name(path):
"""returns the zip filename as string"""
cur_dir = Path(path).resolve()
parent_dir = cur_dir.parents[0]
zip_filename = '{}/{}_{}.zip'.format(parent_dir, cur_dir.name, date_str())
p_zip = Path(zip_filename)
n = 1
while p_zip.exists():
zip_filename = ('{}/{}_{}_{}.zip'.format(parent_dir, cur_dir.name,
date_str(), n))
p_zip = Path(zip_filename)
n += 1
return zip_filename
def all_files(path):
"""iterator returns all files and folders from path as absolute path string
"""
for child in Path(path).iterdir():
yield str(child)
if child.is_dir():
for grand_child in all_files(str(child)):
yield str(Path(grand_child))
def zip_dir(path):
"""generate a zip"""
zip_filename = zip_name(path)
zip_file = zipfile.ZipFile(zip_filename, 'w')
print('create:', zip_filename)
for file in all_files(path):
print('adding... ', file)
zip_file.write(file)
zip_file.close()
if __name__ == '__main__':
zip_dir('.')
print('end!')
答案 9 :(得分：2)
您可能想查看zipfile模块;有http://docs.python.org/library/zipfile.html的文档。
您可能还希望os.walk()索引目录结构。
答案 10 :(得分：1)
如果您想要任何常见图形文件管理器的压缩文件夹之类的功能，您可以使用以下代码，它使用zipfile模块。使用此代码，您将获得zip文件，其路径为根文件夹。
import os
import zipfile
def zipdir(path, ziph):
# Iterate all the directories and files
for root, dirs, files in os.walk(path):
# Create a prefix variable with the folder structure inside the path folder.
# So if a file is at the path directory will be at the root directory of the zip file
# so the prefix will be empty. If the file belongs to a containing folder of path folder
# then the prefix will be that folder.
if root.replace(path,'') == '':
prefix = ''
else:
# Keep the folder structure after the path folder, append a '/' at the end
# and remome the first character, if it is a '/' in order to have a path like
# folder1/folder2/file.txt
prefix = root.replace(path, '') + '/'
if (prefix[0] == '/'):
prefix = prefix[1:]
for filename in files:
actual_file_path = root + '/' + filename
zipped_file_path = prefix + filename
zipf.write( actual_file_path, zipped_file_path)
zipf = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED)
zipdir('/tmp/justtest/', zipf)
zipf.close()
答案 11 :(得分：1)
这里有这么多答案，我希望我可以贡献自己的版本，该版本基于原始答案（顺便说一句），但具有更多的图形化视角，也为每个zipfile设置都使用了上下文并排序os.walk()，以使输出有序。
具有这些文件夹及其文件（以及其他文件夹），我想为每个.zip文件夹创建一个cap_：
$ tree -d
.
├── cap_01
| ├── 0101000001.json
| ├── 0101000002.json
| ├── 0101000003.json
|
├── cap_02
| ├── 0201000001.json
| ├── 0201000002.json
| ├── 0201001003.json
|
├── cap_03
| ├── 0301000001.json
| ├── 0301000002.json
| ├── 0301000003.json
|
├── docs
| ├── map.txt
| ├── main_data.xml
|
├── core_files
├── core_master
├── core_slave
这就是我应用的内容，并带有注释以更好地了解该过程。
$ cat zip_cap_dirs.py
""" Zip 'cap_*' directories. """
import os
import zipfile as zf
for root, dirs, files in sorted(os.walk('.')):
if 'cap_' in root:
print(f"Compressing: {root}")
# Defining .zip name, according to Capítulo.
cap_dir_zip = '{}.zip'.format(root)
# Opening zipfile context for current root dir.
with zf.ZipFile(cap_dir_zip, 'w', zf.ZIP_DEFLATED) as new_zip:
# Iterating over os.walk list of files for the current root dir.
for f in files:
# Defining relative path to files from current root dir.
f_path = os.path.join(root, f)
# Writing the file on the .zip file of the context
new_zip.write(f_path)
基本上，对于os.walk(path)上的每次迭代，我都会打开一个用于zipfile设置的上下文，然后再迭代files，这是一个list文件从root目录开始，根据当前root目录形成每个文件的相对路径，并附加到正在运行的zipfile上下文中。
输出显示如下：
$ python3 zip_cap_dirs.py
Compressing: ./cap_01
Compressing: ./cap_02
Compressing: ./cap_03
要查看每个.zip目录的内容，可以使用less命令：
$ less cap_01.zip
Archive: cap_01.zip
Length Method Size Cmpr Date Time CRC-32 Name
-------- ------ ------- ---- ---------- ----- -------- ----
22017 Defl:N 2471 89% 2019-09-05 08:05 7a3b5ec6 cap_01/0101000001.json
21998 Defl:N 2471 89% 2019-09-05 08:05 155bece7 cap_01/0101000002.json
23236 Defl:N 2573 89% 2019-09-05 08:05 55fced20 cap_01/0101000003.json
-------- ------- --- -------
67251 7515 89% 3 files
答案 12 :(得分：1)
提供更大的灵活性，例如通过名称选择目录/文件使用：
import os
import zipfile
def zipall(ob, path, rel=""):
basename = os.path.basename(path)
if os.path.isdir(path):
if rel == "":
rel = basename
ob.write(path, os.path.join(rel))
for root, dirs, files in os.walk(path):
for d in dirs:
zipall(ob, os.path.join(root, d), os.path.join(rel, d))
for f in files:
ob.write(os.path.join(root, f), os.path.join(rel, f))
break
elif os.path.isfile(path):
ob.write(path, os.path.join(rel, basename))
else:
pass
对于文件树：
.
├── dir
│ ├── dir2
│ │ └── file2.txt
│ ├── dir3
│ │ └── file3.txt
│ └── file.txt
├── dir4
│ ├── dir5
│ └── file4.txt
├── listdir.zip
├── main.py
├── root.txt
└── selective.zip
您可以例如仅选择dir4和root.txt：
cwd = os.getcwd()
files = [os.path.join(cwd, f) for f in ['dir4', 'root.txt']]
with zipfile.ZipFile("selective.zip", "w" ) as myzip:
for f in files:
zipall(myzip, f)
或者只是在脚本调用目录中listdir，然后从那里添加所有内容：
with zipfile.ZipFile("listdir.zip", "w" ) as myzip:
for f in os.listdir():
if f == "listdir.zip":
# Creating a listdir.zip in the same directory
# will include listdir.zip inside itself, beware of this
continue
zipall(myzip, f)
答案 13 :(得分：1)
压缩文件或树（目录及其子目录）。
from pathlib import Path
from zipfile import ZipFile, ZIP_DEFLATED
def make_zip(tree_path, zip_path, mode='w', skip_empty_dir=False):
with ZipFile(zip_path, mode=mode, compression=ZIP_DEFLATED) as zf:
paths = [Path(tree_path)]
while paths:
p = paths.pop()
if p.is_dir():
paths.extend(p.iterdir())
if skip_empty_dir:
continue
zf.write(p)
要追加到现有归档文件，请传递mode='a'，以创建新的归档文件mode='w'（上面的默认设置）。假设您要将3个不同的目录树捆绑在同一个档案中。
make_zip(path_to_tree1, path_to_arch, mode='w')
make_zip(path_to_tree2, path_to_arch, mode='a')
make_zip(path_to_file3, path_to_arch, mode='a')
答案 14 :(得分：1)
现代Python（3.6+）使用pathlib模块进行简洁的OOP处理路径，使用pathlib.Path.rglob()进行递归通配。据我所知，这相当于George V. Reilly的答案：压缩拉链，最顶层的元素是目录，保持空目录，使用相对路径。
from pathlib import Path
from zipfile import ZIP_DEFLATED, ZipFile
from os import PathLike
from typing import Union
def zip_dir(zip_name: str, source_dir: Union[str, PathLike]):
src_path = Path(source_dir).expanduser().resolve(strict=True)
with ZipFile(zip_name, 'w', ZIP_DEFLATED) as zf:
for file in src_path.rglob('*'):
zf.write(file, file.relative_to(src_path.parent))
注意：正如可选类型提示所示，zip_name不能是Path对象（would be fixed in 3.6.2+）。
答案 15 :(得分：1)
使用 pathlib.Path 的解决方案，独立于所使用的操作系统：
import zipfile
from pathlib import Path
def zip_dir(path: Path, zip_file_path: Path):
"""Zip all contents of path to zip_file"""
files_to_zip = [
file for file in path.glob('*') if file.is_file()]
with zipfile.ZipFile(
zip_file_path, 'w', zipfile.ZIP_DEFLATED) as zip_f:
for file in files_to_zip:
print(file.name)
zip_f.write(file, file.name)
current_dir = Path.cwd()
zip_dir = current_dir / "test"
tools.zip_dir(
zip_dir, current_dir / 'Zipped_dir.zip')
答案 16 :(得分：1)
尝试下面的一个。这对我有用。
import zipfile, os
zipf = "compress.zip"
def main():
directory = r"Filepath"
toZip(directory)
def toZip(directory):
zippedHelp = zipfile.ZipFile(zipf, "w", compression=zipfile.ZIP_DEFLATED )
list = os.listdir(directory)
for file_list in list:
file_name = os.path.join(directory,file_list)
if os.path.isfile(file_name):
print file_name
zippedHelp.write(file_name)
else:
addFolderToZip(zippedHelp,file_list,directory)
print "---------------Directory Found-----------------------"
zippedHelp.close()
def addFolderToZip(zippedHelp,folder,directory):
path=os.path.join(directory,folder)
print path
file_list=os.listdir(path)
for file_name in file_list:
file_path=os.path.join(path,file_name)
if os.path.isfile(file_path):
zippedHelp.write(file_path)
elif os.path.isdir(file_name):
print "------------------sub directory found--------------------"
addFolderToZip(zippedHelp,file_name,path)
if __name__=="__main__":
main()
答案 17 :(得分：1)
以下是Nux给出的答案的变体，对我有用：
def WriteDirectoryToZipFile( zipHandle, srcPath, zipLocalPath = "", zipOperation = zipfile.ZIP_DEFLATED ):
basePath = os.path.split( srcPath )[ 0 ]
for root, dirs, files in os.walk( srcPath ):
p = os.path.join( zipLocalPath, root [ ( len( basePath ) + 1 ) : ] )
# add dir
zipHandle.write( root, p, zipOperation )
# add files
for f in files:
filePath = os.path.join( root, f )
fileInZipPath = os.path.join( p, f )
zipHandle.write( filePath, fileInZipPath, zipOperation )
答案 18 :(得分：0)
对于其他研究此问题并尝试将其程序存储在同一目录中并且由于zip文件本身具有压缩性而变得非常深的树形结构并最终以递归的人，请尝试此操作。
这是Mark's answer和一些额外检查的结合，以确保zipfile本身没有递归zip压缩，并且没有不必要的深层文件夹结构。
import os
import zipfile
def zipdir(path, ziph, ignored_directories, ignored_files):
# ziph is zipfile handle
for root, dirs, files in os.walk(path):
for file in files:
if not any(ignored_dir in root for ignored_dir in ignored_directories):
if not any(ignored_fname in file for ignored_fname in ignored_files):
ziph.write(os.path.join(root, file))
# current working directory
this_dir = os.path.dirname(os.path.abspath(__file__))
# the directory within the working directory the zip will be created in (build/archives).
zip_dest_dir = os.path.join('build', 'archives')
# verify zip_dest_dir exists: if not, create it
if not os.path.isdir(zip_dest_dir):
os.makedirs(zip_dest_dir, exist_ok=True)
# leave zip_dest_dir blank (or set dist_dir = this_dir) if you want the zip file in the working directory (same directory as the script)
dest_dir = os.path.join(this_dir, zip_dest_dir)
# name the zip file: remember the file extension
zip_filename = 'zipped_directory.zip'
# zip file's path
zip_path = os.path.join(dest_dir, zip_filename)
# create the zipfile handle: you can change ZIP_STORED to any other compression algorithm of your choice, like ZIP_DEFLATED, if you need actual compression
zipf = zipfile.ZipFile(zip_path, 'w', zipfile.ZIP_STORED)
# ignored files and directories: I personally wanted to ignore the "build" directory, alongside with "node_modules", so those would be listed here.
ignored_dirs = []
# ignore any specific files: in my case, I was ignoring the script itself, so I'd include 'deploy.py' here
ignored_files = [zip_filename]
# zip directory contents
zipdir('.', zipf, ignored_dirs, ignored_files)
zipf.close()
生成的zip文件应仅包含从工作目录开始的目录：因此，不能包含Users / user / Desktop / code /.../ working_directory /.../ etc。一种文件结构。
答案 19 :(得分：0)
显而易见的方法是使用shutil，就像第二个顶级答案所说的那样，但是如果您出于某种原因仍然希望使用ZipFile，并且如果您在这样做时遇到一些麻烦（例如ERR 13 in Windows 等），您可以使用此修复程序：
import os
import zipfile
def retrieve_file_paths(dirName):
filePaths = []
for root, directories, files in os.walk(dirName):
for filename in files:
filePath = os.path.join(root, filename)
filePaths.append(filePath)
return filePaths
def main(dir_name, output_filename):
filePaths = retrieve_file_paths(dir_name)
zip_file = zipfile.ZipFile(output_filename+'.zip', 'w')
with zip_file:
for file in filePaths:
zip_file.write(file)
main("my_dir", "my_dir_archived")
这个递归遍历给定文件夹中的每个子文件夹/文件，并将它们写入一个 zip 文件，而不是尝试直接压缩文件夹。
答案 20 :(得分：0)
以简洁的方式将文件夹层次结构保留在要归档的父目录下：
import glob
import zipfile
with zipfile.ZipFile(fp_zip, "w", zipfile.ZIP_DEFLATED) as zipf:
for fp in glob(os.path.join(parent, "**/*")):
base = os.path.commonpath([parent, fp])
zipf.write(fp, arcname=fp.replace(base, ""))
如果需要，可以将其更改为使用pathlib for file globbing。
答案 21 :(得分：0)
说要压缩当前目录中的所有文件夹（子目录）。
for root, dirs, files in os.walk("."):
for sub_dir in dirs:
zip_you_want = sub_dir+".zip"
zip_process = zipfile.ZipFile(zip_you_want, "w", zipfile.ZIP_DEFLATED)
zip_process.write(file_you_want_to_include)
zip_process.close()
print("Successfully zipped directory: {sub_dir}".format(sub_dir=sub_dir))
答案 22 :(得分：0)
用于创建zip文件的功能。
def CREATEZIPFILE(zipname, path):
#function to create a zip file
#Parameters: zipname - name of the zip file; path - name of folder/file to be put in zip file
zipf = zipfile.ZipFile(zipname, 'w', zipfile.ZIP_DEFLATED)
zipf.setpassword(b"password") #if you want to set password to zipfile
#checks if the path is file or directory
if os.path.isdir(path):
for files in os.listdir(path):
zipf.write(os.path.join(path, files), files)
elif os.path.isfile(path):
zipf.write(os.path.join(path), path)
zipf.close()
答案 23 :(得分：0)
好吧，在阅读了建议之后，我想到了一种与2.7.x十分相似的方式，而不创建“有趣的”目录名称（类似绝对的名称），并且只会在zip内创建指定的文件夹。
或者，以防万一，您需要在zip文件中包含一个包含所选目录内容的文件夹。
def zipDir( path, ziph ) :
"""
Inserts directory (path) into zipfile instance (ziph)
"""
for root, dirs, files in os.walk( path ) :
for file in files :
ziph.write( os.path.join( root, file ) , os.path.basename( os.path.normpath( path ) ) + "\\" + file )
def makeZip( pathToFolder ) :
"""
Creates a zip file with the specified folder
"""
zipf = zipfile.ZipFile( pathToFolder + 'file.zip', 'w', zipfile.ZIP_DEFLATED )
zipDir( pathToFolder, zipf )
zipf.close()
print( "Zip file saved to: " + pathToFolder)
makeZip( "c:\\path\\to\\folder\\to\\insert\\into\\zipfile" )
答案 24 :(得分：0)
# import required python modules
# You have to install zipfile package using pip install
import os,zipfile
# Change the directory where you want your new zip file to be
os.chdir('Type your destination')
# Create a new zipfile ( I called it myfile )
zf = zipfile.ZipFile('myfile.zip','w')
# os.walk gives a directory tree. Access the files using a for loop
for dirnames,folders,files in os.walk('Type your directory'):
zf.write('Type your Directory')
for file in files:
zf.write(os.path.join('Type your directory',file))
答案 25 :(得分：0)
我通过整合Mark Byers＆＃39;来准备一个功能。 Reimund和Morten Zilmer的评论（相对路径和包括空目录）的解决方案。作为最佳实践，with用于ZipFile的文件构建。
该功能还准备了一个默认的zip文件名，其中包含压缩的目录名和＆＃39; .zip＆＃39;延期。因此，它只使用一个参数：要压缩的源目录。
import os
import zipfile
def zip_dir(path_dir, path_file_zip=''):
if not path_file_zip:
path_file_zip = os.path.join(
os.path.dirname(path_dir), os.path.basename(path_dir)+'.zip')
with zipfile.ZipFile(path_file_zip, 'wb', zipfile.ZIP_DEFLATED) as zip_file:
for root, dirs, files in os.walk(path_dir):
for file_or_dir in files + dirs:
zip_file.write(
os.path.join(root, file_or_dir),
os.path.relpath(os.path.join(root, file_or_dir),
os.path.join(path_dir, os.path.pardir)))
答案 26 :(得分：0)
这是一种使用pathlib和上下文管理器的现代方法。将文件直接放在zip中，而不是放在子文件夹中。
def zip_dir(filename: str, dir_to_zip: pathlib.Path):
with zipfile.ZipFile(filename, 'w', zipfile.ZIP_DEFLATED) as zipf:
# Use glob instead of iterdir(), to cover all subdirectories.
for directory in dir_to_zip.glob('**'):
for file in directory.iterdir():
if not file.is_file():
continue
# Strip the first component, so we don't create an uneeded subdirectory
# containing everything.
zip_path = pathlib.Path(*file.parts[1:])
# Use a string, since zipfile doesn't support pathlib directly.
zipf.write(str(file), str(zip_path))