Question

问题，我想使用会话，但是我遇到了从$ food数组实现会话的问题，如果用户选择了Pizza，我不会给他或她提供三明治，同样如果用户选择Sandwitch，我不向用户提供比萨饼。

我还想知道用户是否已经选择了比萨饼或三明治。

  $food = array("Pizza" => $_POST["pepperoni"], "Sandwitch"=>$_POST["chickensandwitch"]);

//How do I set up each $food element such that it gets its own session?
// In addition to checking if  $food["Pizza"] has been selected or not?
if (isset($_SESSION('$food["Pizza"]')))
{
$_SESSION('$food["Pizza"]') = $_SESSION('$food["Pizza"]') 
echo "You have already selected Pepperoni";
}
else
{
echo "Please select  a Pizza";
}

PS，关于上面代码的结构和语法，我知道有很多问题，这就是为什么我要求帮助，谢谢你没有火红，Newb。

Answer 1

//How do I set up each $food element such that it gets its own session?

结构应该是这样的：

$_SESSION['food']['pizza'] = 'pepperoni';
$_SESSION['food']['sandwich'] = 'chicken sandwich';

// checking if food[pizza]has been selected/defined
if( isset($_SESSION['food']['pizza']) ) {
    echo "You've already selected " . $_SESSION['food']['pizza'];
} else {
    echo "Please select a Pizza";
}

Answer 2

您的代码实际上存在一些问题，我也不明白您的问题。这是我认为你需要的一个例子。

if( !isset($_SESSION['food']) ) {
    if( isset($_POST['food']) ) {
        $_SESSION['food'] = $_POST['food'];
    } else {
        die( "You'll have to select whicht type of food you want." );
    }
}

if( $_SESSION['food']=="Pizza" ) {
    // User selected pizza
    if( isset($_POST['pizza']) ) {
        // User selected a type of pizza
        $_SESSION['pizza'] = $_POST['pizza'];
    } else if( !isset($_SESSION['pizza']) ) {
        // No pizza selected by user and also none in session
        die( "You'll have to select a pizza." );
    } else {
        // User selected type of pizza previously
        echo htmlspecialchars( "You selected pizza '{$_SESSION['pizza']}'." ) . "<br />\n";
    }
} else if( $_SESSION['food']=="Sandwhich" ) {
    // Same as above just for sandwhiches..
} else {
    echo "No pizza or other food selected.";
}

php会话并确定是否已通过会话选择了x值

2 个答案: