我正在尝试将Parcelable数据从一个意图传递到另一个意图,这是我得到的错误:
08-31 14:12:22.709: E/AndroidRuntime(9931): FATAL EXCEPTION: main
08-31 14:12:22.709: E/AndroidRuntime(9931): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.matejsoftware.cardscoretracker/com.matejsoftware.cardscoretracker.Igra}: android.os.BadParcelableException: Parcelable protocol requires a Parcelable.Creator object called CREATOR on class com.matejsoftware.cardscoretracker.Novaigra$Player
问题是:我确实有Parcelable.Creator对象。我将在下面发布整个Parcelable代码:
public class Player implements Parcelable{
String name;
int score;
@Override
public int describeContents() {
// TODO Auto-generated method stub
return 0;
}
@Override
public void writeToParcel(Parcel dest, int flags) {
dest.writeString(name);
dest.writeInt(score);
}
public Player(Parcel source){
score = source.readInt();
name = source.readString();
}
public Player(int score, String name){
this.score = score;
this.name = name;
}
}
public class MyCreator implements Parcelable.Creator<Player> {
@Override
public Player createFromParcel(Parcel source) {
return new Player(source);
}
@Override
public Player[] newArray(int size) {
return new Player[size];
}
}
CREATOR有什么不对吗?单击按钮开始下一个活动时,应用程序崩溃。
这是我在第二个活动中“检索”Parcelable数据的方式:
//global variable
ArrayList<Player> playersParceledData;
//This is in onCreate
playersData = getIntent();
playersParceledData = playersData.getParcelableArrayListExtra("parceledData");
此外,这是我将类对象放到ParcelableArrayListExtra的方式:
Player newPlayer = new Player(0, text);
playersParceledData.add(newPlayer);
zacniIgro.putParcelableArrayListExtra("parceledData", playersParceledData);
答案 0 :(得分:31)
从Parcel阅读时,您的序列与您写入的序列不同。
在writeToParcel()
中,您首先放置String,但在HeatFriendDetail(Parcel in)
中,您首先读取整数。这不是正确的方法,因为订单或读/写很重要。
以下是在向/从Parcel写入/读取数据时执行正确顺序的代码(另请参阅this link):
public class FriendDetail implements Parcelable {
private String full_name;
private int privacy;
public HeatFriendDetail(Parcel in) {
this.full_name = in.readString();
this.privacy = in.readInt();
}
public HeatFriendDetail() {
}
@Override
public void writeToParcel(Parcel dest, int flags) {
dest.writeString(this.full_name);
dest.writeInt(this.privacy);
}
public static final Parcelable.Creator CREATOR = new Parcelable.Creator() {
public HeatFriendDetail createFromParcel(Parcel in) {
return new HeatFriendDetail(in);
}
public HeatFriendDetail[] newArray(int size) {
return new HeatFriendDetail[size];
}
};
// GETTER SETTER//
}
答案 1 :(得分:6)
我仅在发布apk中收到此错误,因为CREATOR不公开。
我改变了这个:
static final Parcelable.Creator<Station> CREATOR = new Parcelable.Creator<Station>() {
对此:
public static final Parcelable.Creator<Station> CREATOR = new Parcelable.Creator<Station>() {
答案 2 :(得分:3)
刚碰到这个。
我有预感,我查看了我的ProGuard映射文件。
通常我会像这样声明CREATOR:
public static final Parcelable.Creator<ClassA> CREATOR =
new Parcelable.Creator<ClassA>() {
显示在映射文件中,如下所示:
android.os.Parcelable$Creator CREATOR -> CREATOR
..除了一个类,报告错误的类。我宣布这样:
public static Creator<ClassB> CREATOR =
new Creator<ClassB>() {
瞧瞧:
android.os.Parcelable$Creator CREATOR -> a
因此,如果您在生产版本中收到此异常,请检查您的映射文件。我认为ProGuard在决定不混淆CREATOR时非常敏感。
答案 3 :(得分:2)
当CREATOR类不是静态时,我收到此错误消息
答案 4 :(得分:1)
如果您使用的是Proguard规则,请将此行添加到您的proguard-rules.pro
-keepnames class * implements android.os.Parcelable {
public static final ** CREATOR;
}
答案 5 :(得分:-1)
试试这种方式
// create List of player
ArrayList<HashMap<String, String>> players = new ArrayList<HashMap<String, String>>();
//create Player
HashMap<String, String> player = new HashMap<String, String>();
player.put("score", "20");//replace 20 with your score variable
player.put("name", "Biraj");//replace Biraj with your name variable
// Add to arraylist
players.add(player);
// pass to intent
Intent i;
i.putExtra("PLAYERS", players);
// read From intent
ArrayList<HashMap<String, String>> playerFromintent = (ArrayList<HashMap<String, String>>) getIntent().getSerializableExtra("PLAYERS");
// read from ArrayList
for (HashMap<String, String> hashMap : playerFromintent) {
System.out.println("Name : " + hashMap.get("name"));
System.out.println("Score : " + hashMap.get("score"));
}