我试图摆脱未定义的索引。每次我点击提交时都不勾选方框,我得到一个未定义的索引错误。
<html>
<head>
<title>Order</Title>
<style>
</style>
<body>
<form action = "order.php" method = "post">
Coffee:<p>
<input type = "checkbox" value = "coffee" name = "cappuccino"/>Capuccino<br>
</form>
</body>
</head>
</Html>
<?php
$capuccino = 3.75;
if(isset($_POST["submit"]))
{
if($_POST['cappuccino'] <> 'coffee')
{
$capuccino = 0;
}
}
?>
答案 0 :(得分:1)
尝试isset
喜欢
<?php
if(isset($_POST["submit"]))
{
if(isset($_POST['cappuccino']) && $_POST['cappuccino'] <> 'coffee')
{
$capuccino = 0;
}
}
?>
您也可以使用!=
代替<>
$_POST['cappuccino'] != 'coffee'
答案 1 :(得分:1)
在HTML表单中,如果不进行检查,则不会发布值。你应该测试它是否是先发布的,所以你的php代码应该是这样的:
<?php
if(isset($_POST["submit"]))
{
if(isset($_POST['cappuccino']) && $_POST['cappuccino'] <> 'coffee')
{
$capuccino = 0;
}
}
?>
答案 2 :(得分:0)
你的条件应该是:
if(array_key_exists('cappuccino', $_POST) && isset($_POST['cappuccino']) && $_POST['cappuccino'] <> 'coffee')
答案 3 :(得分:0)
<html>
<head>
<title>Order</Title>
<style>
</style>
<body>
<form action = "order.php" method = "post">
Coffee:<p>
<input type = "checkbox" value = "coffee" name = "cappuccino"/>Capuccino<br>
<input type="submit" name="submit" value="Submit" />
</form>
</body>
</head>
</Html>
<?php
$capuccino = 3.75;
if(isset($_POST["submit"]))
{
if(isset($_POST['cappuccino']) && !empty($_POST['cappuccino']) <> 'coffee')
{
$capuccino = 0;
}
}
?>