由于评论中有以下建议,我已更新了我的代码。现在的问题是我得到一个错误。这是新代码:
<?php
require_once "config.php";
$idspam = "1";
$sql = "SELECT * FROM company WHERE ID = '$idspam'";
$result = mysql_query($sql);
while ($row = mysql_fetch_array($result))
{
$companyname = $row['CompanyName'];
}
$sql = "SELECT * FROM users";
$result = mysql_query($sql);
$rows = mysql_fetch_array($result);
foreach($rows as $row)
{
$Agent = $row['username'];
$fullname = $row['fullname'];
$phone = $row['phone'];
$Agentmail = $row['mail'];
$checkstat = "New customer";
$result = mysql_query("SELECT * FROM data WHERE Status = '$checkstat' AND Agent = '$Agent'");
$rows = mysql_fetch_array($result);
foreach($rows as $row)
{
$LastName = $row['LastName'];
if (empty($row['ProductPriceUSD'])) {
$ProductPriceEUR = $row['ProductPriceEUR'];
$symbol = "€";
$Productprice = ($ProductPriceEUR . $symbol);
}
if (empty($row['ProductPriceEUR'])) {
$ProductPriceUSD = $row['ProductPriceUSD'];
$symbol = "$";
$Productprice = ($symbol . $ProductPriceUSD);
}
$CustomerPriceRAW = $row['CustomerPrice'];
$eur = "€";
$email = $row['Email'];
$a = mt_rand(100000,999999);
$MD5Pass = md5($LastName . $a);
$type = "Initial";
$sql = "SELECT * FROM emails WHERE AddedBy = '$Agent' ORDER BY RAND() LIMIT 1";
$result = mysql_query($sql);
while ($row = mysql_fetch_array($result))
{
$content = $row['Content'];
$subject = $row['Subject'];
}
$Newstatus = "Contacted";
$Newline = "<br>";
$replaceWord = array(
"[name]" => $row['FirstName'],
"[lastname]" => $row['LastName'],
"[product]" => $row['ProductName'],
"[username]" => $row['CustomerUser'],
"[agent]" => $row['Agent'],
"[productssold]" => $row['ProductsSold'],
"[customerprice]" => ($CustomerPriceRAW . $eur),
"[password]" => ($LastName . $a),
"[productprice]" => $Productprice,
"[newline]" => $Newline,
);
ob_start();
include("./email/mailtemplate.php");
$sendmsg = ob_get_clean();
$message = $sendmsg;
$body = strtr($content, $replaceWord);
$headers = "From:".$companyname." ".$Agentmail."\r\n";
$headers .= "MIME-Version: 1.0\r\n";
$headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n";
$contactdate = date("Y-m-d");
$sevendays = date('Y-m-d', strtotime("+7 days"));
$todo = "Followup";
mysql_query("UPDATE data SET CustomerPass = '$MD5Pass', Status = '$Newstatus', Contacted = '$contactdate', SevenDays = '$sevendays', ToDo = '$todo'");
mail($email, $subject, $body, $headers);
}
}
?>
这是我得到的错误
Warning: Invalid argument supplied for foreach() in /home/user/public_html/cronmailinitial.php on line 22
为什么呢?我想挑选所有员工(第一个foreach)并联系他们的每个客户。所以一个例子是: 代理人“约翰” 选择由“John”添加的所有客户 对于他们每个人选择一个不同的电子邮件模板 发送
这就是它无论如何都要做的事情。提前致谢
答案 0 :(得分:1)
两件事:
更改所有
while($ row = mysql_fetch_array($ result))
更像是
$rows = mysql_fetch_array( $result );
foreach( $rows as $row )
{
.. do something with $row....
}