Question

我想在其他表单关闭时取消选中ContextMenuStrip项。这是我的代码：

Form1中：

   public bool ischecked
    {
        get { return openForm1ToolStripMenuItem.Checked; }
        set { openForm1ToolStripMenuItem.Checked = value; }
    }

    bool isForm2Open = false;
    bool isForm3Open = false;

    private void openForm1ToolStripMenuItem_Click(object sender, EventArgs e)
    {
        if (!isForm2Open)
        {
            Form2 frm2 = new Form2();
            frm2.Show();
            isForm2Open = true;
            openForm1ToolStripMenuItem.Checked = true;
        }
        else
        {
            openForm1ToolStripMenuItem.Checked = false;
            isForm2Open = false;
        }
    }

窗体2：

private void Form2_FormClosed(object sender, FormClosedEventArgs e)
{
    // Code for Unckeck openForm1ToolStripMenuItem
}

为什么缺乏其他形式的缺血？

Answer 1

private void openForm1ToolStripMenuItem_Click(object sender, EventArgs e) {
    ToolStripMenuItem item = sender as ToolStripMenuItem;
    if (!isForm2Open)
    {
        Form2 frm2 = new Form2();
        frm2.FormClosed += (s,ev) => {
           item.Checked = false;
           isForm2Open = false;
        };
        frm2.Show();
        isForm2Open = true;
        openForm1ToolStripMenuItem.Checked = true;
    }
    else
    {
        openForm1ToolStripMenuItem.Checked = false;
        isForm2Open = false;
    }
}

Answer 2

您可以将表单显示为此对话框

 frm2.ShowDialog();

或者你必须在form2中创建一个事件。在表单关闭时触发。您将在表单1中注册该事件，然后取消选中您的框。

在表格2中声明事件，如

 public event EventHandler onFormClosed;

然后是Form2的结束事件

 private void Form2_FormClosed(object sender, FormClosedEventArgs e)
 {
    if(onFormClosed!= null)
          onFormClosed(this,EventArgs.Empty);
 }

然后以你的形式1

 Form2 frm2 = new Form2();
 frm.onFormClosed += frm_onFormClosed;
 frm2.Show();

这将创建一个像这样的方法

 private void frm_onFormClosed(object sender, EventArgs e)
 {
    if (this.InvokeRequired)
    {   
        this.Invoke(() =>  openForm1ToolStripMenuItem.Checked = false);
    }
    else
    {
       openForm1ToolStripMenuItem.Checked = false;
    }

 }

Answer 3

您需要引用第二种形式的第一个表单才能更改其属性。此外，上述两个答案是完成此任务的更好方法，即使他们没有直接回答所提出的问题。：）

Form1中：

   public bool ischecked
    {
        get { return openForm1ToolStripMenuItem.Checked; }
        set { openForm1ToolStripMenuItem.Checked = value; }
    }

    bool isForm2Open = false;
    bool isForm3Open = false;

    private void openForm1ToolStripMenuItem_Click(object sender, EventArgs e)
    {
        if (!isForm2Open)
        {
            Form2 frm2 = new Form2();
            frm2.MainForm = this;
            frm2.Show();
            isForm2Open = true;
            openForm1ToolStripMenuItem.Checked = true;
        }
        else
        {
            openForm1ToolStripMenuItem.Checked = false;
            isForm2Open = false;
        }
    }

窗体2：

public Form MainForm { get; set; }

private void Form2_FormClosed(object sender, FormClosedEventArgs e)
{
  this.MainForm.ischecked = false;
}

取消选中其他表单关闭时的ContextMenuStrip项

3 个答案: