Question

我有以下身份验证处理程序：

class LoginAuthSuccessHandler implements AuthenticationSuccessHandlerInterface, AuthenticationFailureHandlerInterface
{
    private $router;
    private $container;

    /**
    * Constructor
    * @param RouterInterface   $router
    */
    public function __construct(RouterInterface $router, $container)
    {
        $this->router = $router;
        $this->container = $container;
    }

    public function onAuthenticationSuccess(Request $request, TokenInterface $token)
    {
        if ($request->isXmlHttpRequest()) {
            $user =  $this->container->get('security.context')->getToken()->getUser();
            $result = array('success' => true, 'user' => $user);
            return new Response(json_encode($result));
        } else {
            $route = $this->router->generate('ShopiousMainBundle_profile');

            $referrer_url = $request->server->get('HTTP_REFERER');
            if (strstr($referrer_url, '/items/')) {
                 $route = $referrer_url;
            }

            return new RedirectResponse($route);
        }
    }

    public function onAuthenticationFailure(Request $request, AuthenticationException $exception)
    {
        if ($request->isXmlHttpRequest()) {
            $result = array('success' => false, 'message' => $exception->getMessage());
            return new Response(json_encode($result));
        } else {
            // Handle non XmlHttp request here
        }
    }
}

为什么会这样：

$user =  $this->container->get('security.context')->getToken()->getUser();

返回null？我如何在此时获得经过身份验证的用户？

Answer 1

您应该使用您收到的$token变量作为参数，而不是$this->container->get('security.context')->getToken()。

$user = $token->getUser();

Answer 2

maibe你没有在security.yml中设置你的提供者。

security:
 provider:
  example:
   entity: {class Acme\AuctionBundle\Entity\User, property: username}

用您的替换Bundle和实体。

Answer 3

我找到的唯一方法是注入entityManager，

calls:
    - [setEntityManager,[@doctrine.orm.entity_manager]]

使用该用户名从请求中获取用户名并查询该用户。

$userRepo->findByEmail($request->get('_username'));

Answer 4

public function onAuthenticationSuccess(Request $request, TokenInterface $token)
{
    $user = $token->getUser();
}

这就是全部;）

获取经过身份验证的用户onAuthenticationSuccess

4 个答案: