Question

如何构建HTTP POST请求的URL？

Answer 1

你确定要发帖吗？以上网址看起来像GET。

<html><head>
<meta http-equiv="content-type" content="text/html;charset=utf-8">
<title>405 HTTP method GET is not supported by this URL</title>
</head>
<body text=#000000 bgcolor=#ffffff>
<h1>Error: HTTP method GET is not supported by this URL</h1>
</body></html>

Answer 2

根据API documentation，您应该将JSON数据作为POST方法的请求主体传递，而不是作为URL参数传递。

所以看起来应该是这样的：

String data = "{\"data\": [{\"text\": \"I love Titanic.\"}, {\"text\": \"I hate Titanic.\"}]}";

URL url = new URL("http://www.sentiment140.com/api/bulkClassifyJson?appid=me@gmail.com");
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setRequestMethod("POST");

// write the request body
connection.getOutputStream().write(data.getBytes("UTF8"));

// get the response and read it
InputStream in = connection.getInputStream();

如何构建HTTP POST请求的URL？

2 个答案: