对如何组合两个查询的结果感到困惑

时间:2013-08-29 21:01:55

标签: php mysql sql

查询1:

SELECT count(id) as conversions, SUM(user_payout) as amount, geoip.country_name, geoip.country_code
FROM conversions
LEFT JOIN geoip ON conversions.end_ip BETWEEN geoip.start_long AND geoip.end_long
WHERE user_id = 1
AND type != ''
AND status = 1
AND month(created_at) = month(now())
GROUP BY country_name
ORDER BY country_name ASC

结果:
Query results

查询2:

SELECT count(id) as clicks, geoip.country_name, geoip.country_code
FROM clicks
LEFT JOIN geoip on clicks.ip BETWEEN geoip.start_long AND geoip.end_long
WHERE user_id = 1
AND month(created_at) = month(now())
GROUP BY country_name
ORDER BY country_name ASC

结果:
Query results

我想将这两者合并为每个国家/地区,它会显示点击次数,转化次数,country_name和country_code。

无法弄清楚如何做到这一点。

谢谢!

2 个答案:

答案 0 :(得分:2)

您可以使用子查询和left outer join

组合它们
select clicks.country_code, clicks.country_name,
       coalesce(clicks.clicks, 0) as clicks,
       coalesce(conversions.conversions, 0) as conversions
from (<subquery 2>) clicks left outer join
     (<subquery 1>) conversions
     on clicks.country_code = conversions.country_code;

这假设所有国家/地区至少有一次点击。

编辑:

如果国家/地区列表位于geo_ip,您可以执行以下操作:

select gi.country_code, gi.country_name, clicks.clicks, conversions.conversions
from (select distinct country_code, country_name
      from geo_ip
     ) gi left outer join
     (<subquery 2>) clicks
     on clicks.country_code = gi.country_code left outer join
     (<subquery 1>) conversions
     on conversions.country_code = gi.country_code;

答案 1 :(得分:0)

左连接点击第一个查询以进行geoip。

或者您可以使用联盟但是您只需在select语句中选择那些结果,就可以将每个结果仅显示点击次数,转化次数,country_name和country_code。