Powershell启动进程脚本调用第二个脚本 - 如何仅创建一个脚本

时间:2013-08-29 20:19:19

标签: powershell parameter-passing elevated-privileges start-process

我有一个powershell脚本,它接受“sender-ip = 10.10.10.10”形式的参数,并且使用提升的凭证完美运行

#script.ps1

$userID=$NULL
$line_array = @()
$multi_array = @()
[hashtable]$my_hash = @{}

foreach ($i in $args){
   $line_array+= $i.split(" ")
}

foreach ($j in $line_array){
    $multi_array += ,@($j.split("="))
}

foreach ($k in $multi_array){
    $my_hash.add($k[0],$k[1])
}

$Sender_IP = $my_hash.Get_Item("sender-ip")


<#Gather information on the computer corresponding to $Sender_IP#>
$Win32OS = Get-WmiObject -Class Win32_OperatingSystem -ComputerName $Sender_IP 

<#Determine the build number#>
$Build = $Win32OS.BuildNumber


<#Running Windows Vista with SP1 and later, i.e. $Build is greater than or equal to 6001#>
if($Build -ge 6001){
    $Win32User = Get-WmiObject -Class Win32_UserProfile -ComputerName $Sender_IP
    $Win32User = $Win32User | Sort-Object -Property LastUseTime -Descending
    $LastUser = $Win32User | Select-Object -First 1
    $UserSID = New-Object System.Security.Principal.SecurityIdentifier($LastUser.SID)
    $userId = $UserSID.Translate([System.Security.Principal.NTAccount])
    $userId = $userId.Value
}

<#Running Windows Vista without SP1 and earlier, i.e $Build is less than or equal to 6000#>
elseif ($Build -le 6000){
    $SysDrv = $Win32OS.SystemDrive
    $SysDrv = $SysDrv.Replace(":","$")
    $ProfDrv = "\\" + $Sender_IP + "\" + $SysDrv
    $ProfLoc = Join-Path -Path $ProfDrv -ChildPath "Documents and Settings"
    $Profiles = Get-ChildItem -Path $ProfLoc
    $LastProf = $Profiles | ForEach-Object -Process {$_.GetFiles("ntuser.dat.LOG")}
    $LastProf = $LastProf | Sort-Object -Property LastWriteTime -Descending | Select-Object -First 1
    $userId = $LastProf.DirectoryName.Replace("$ProfLoc","").Trim("\").ToUpper()
}

else{
    $userId = "Unknown/UserID"
}

if ($userId -ne $NULL){
    return "userId=" + $userId
}
elseif ($userID -eq $NULL)
{
    $userId = "Unknown/UserID"
    return "userId=" + $userId
}

由于此脚本将由不使用提升凭据的第三方程序调用,因此我必须创建第二个包含提升权限(第三方程序将调用)的PowerShell脚本

#elevated.ps1

[string]$abc = $args

<#Previously created password file in C:\Script\cred.txt, read-host -assecurestring | convertfrom-securestring | out-file C:\Script\cred.txt#>

$password = get-content C:\Script\cred.txt | convertto-securestring
$credentials = new-object -typename System.Management.Automation.PSCredential -argumentlist "DOMAIN\Username",$password


[string]$output = start-process powershell -Credential $credentials -ArgumentList '-noexit','-File', 'C:\script\script.ps1', $abc

return $output

我可以用

手动调用elevated.ps1
.\elevated.ps1 "sender-ip=10.10.10.10"

如何在一个脚本中创建这个脚本,而不是有两个脚本,即一个脚本,其中start-process调用另一个脚本?我相信这会简化参数传递,因为第三方程序必须调用调用script.ps1的elevate.ps1,并且某些错误发生在某处。

2 个答案:

答案 0 :(得分:4)

Windows不允许进程在运行时提升。有一些技巧但是以这种或那种方式他们将产生具有提升权限的新进程。有关详细信息,请参阅here。因此,PowerShell最简单的方法仍然是使用一个脚本来启动 - 处理升级的其他脚本。

答案 1 :(得分:1)

与我的男人迪尔伯特相反,我说这可以做到。只需使用内置"$myInvocation.MyCommand.Definition"这是一个秘密变量来获取正在运行的脚本的完整路径。编写循环语句以验证是否以Admin身份运行,如果不是,则使用$ myIvocation.MyCommand.Definition作为参数进行start-process。

将此文件放在脚本的顶部。如果处于UAC模式,您将收到确认提示。在Write-Host开始的末尾添加提升的脚本。

$WID=[System.Security.Principal.WindowsIdentity]::GetCurrent();
$WIP=new-object System.Security.Principal.WindowsPrincipal($WID);
$adminRole=[System.Security.Principal.WindowsBuiltInRole]::Administrator;
If ($WIP.IsInRole($adminRole)){
}else {
  $newProcess = new-object System.Diagnostics.ProcessStartInfo 'PowerShell';
  $newProcess.Arguments = $myInvocation.MyCommand.Definition
  $newProcess.Verb = 'runas'
  [System.Diagnostics.Process]::Start($newProcess);Write-Host 'Prompting for Elevation'
  exit
}

Write-Host 'ElevatedCodeRunsHere';
Write-Host 'Press any key to continue...'
$null = $Host.UI.RawUI.ReadKey('NoEcho,IncludeKeyDown')

以下是一些start process示例