如何在c#中发送USSD命令时检索响应结果?

时间:2013-08-29 17:20:15

标签: c# modem ussd

我使用以下代码发送了USSD命令:

SerialPort port = new SerialPort();

port.BaudRate = 921600;
port.PortName = "COM16";
port.Parity = Parity.None;
port.DataBits = 8;
port.StopBits = StopBits.One;
port.ReadTimeout = 3000;
port.WriteTimeout = 3000;
port.DataReceived += port_DataReceived;

port.Open();

port.Write("AT+CUSD=1,\"*140*1#\"" + "\r\n");

void port_DataReceived(object sender, SerialDataReceivedEventArgs e)
{
        SerialPort spL = (SerialPort)sender;
        byte[] buf = new byte[spL.BytesToRead];
        spL.Read(buf, 0, buf.Length);

        foreach (Byte b in buf)
        {
            message += b.ToString();
        }

        var result = Encoding.ASCII.GetString(buf);//just return OK
    }

为什么只在结果中检索OK?

在这种情况下,我想要检索我的余额,我必须得到这样的答案:“你的余额是100美元......”但只需检索:“AT + CUSD = 1,\”* 140 * 1#\“ \ r \ n \ OK \ r \ n“但是当我通过调制解调器自己的应用程序发送此命令时,从运营商处检索到正确的响应,这意味着我的发送命令没问题,但该应用程序收到所有答案,但我收到了一半。

2 个答案:

答案 0 :(得分:1)

实际上我更新了代码,现在它可以与GSMCOMM库一起使用。我可以查看余额并查看回复。我只是将响应附加到字符串变量,而我仍然收到回复。

public string SendUssdRequest(string request)
    {
        log.DebugFormat("Sending USSD Request {0}", request);
        string result = "";
        try
        {
            IProtocol protocol = comm.GetProtocol();
            string gottenString = protocol.ExecAndReceiveMultiple("AT+CUSD=1," + request + ",15");
            result = gottenString;
            int i = 0;
            if (!gottenString.Contains("\r\n+CUSD: 2"))
            {
                bool receiving = false;
                do
                {
                    receiving = protocol.Receive(out gottenString);
                    result += gottenString;
                    ++i;
                } while (receiving);
            }

            result = result.Replace("\r\n", "");

            result = result.Replace("+CUSD: 2,", "");
            result = result.Replace(",15", "");
            log.DebugFormat("{1} - USSD Response is:  {0}", result,SenderNumber);
            return result;
        }
        catch(Exception ex) 
        {
            log.Error(ex);
        }
        finally
        {

            comm.ReleaseProtocol();
        }
        return "";
    }

答案 1 :(得分:-1)

在代码末尾

port.Write("AT+CUSD=1,\"*140*1#\"" + ",15\r");