过滤多维JSON数组

Question

以下是JSON详细信息：

var array={
    "app": {
        "categories": {
            "cat_222": {
                "id": "555",
                "deals": [{
                    "id": "73",
                    "shop": "JeansWest"
                },
                {
                    "id": "8630",
                    "shop": "Adidas"

                },
                {
                    "id": "11912",
                    "shop": "Adidas"
                }]
            },
            "cat_342": {
                "id": "232",
                "deals": [{
                    "id": "5698",
                    "shop": "KFC"
                },
                {
                    "id": "5701",
                    "shop": "KFC"
                },
                {
                    "id": "5699",
                    "shop": "MC"
                }]
            }
        }
    }
}

我尝试过滤数组，使shop包含da模式。

var filted = _.filter(array.app.categories,function(item) {
    return _.any(item.deals,function(c) {
        return c.shop.indexOf('da') != -1;
    });
});

====== UPDATE ===================================== ========================

刚才想通了，这段代码很有用。但它返回的内容如下：

[{
"id": "555",
"deals": [{
    "id": "73",
    "shop": "JeansWest"
}, {
    "id": "8630",
    "shop": "Adidas"
}, {
    "id": "11912",
    "shop": "Adidas"
}]
}]

理想情况下，我想得到这样的东西：

[{
"id": "555",
"deals": [{

    "id": "8630",
    "shop": "Adidas"
}, {
    "id": "11912",
    "shop": "Adidas"
}]
}]

Answer 1

你可以这样做

var filted = _.reduce(array.app.categories, function (memo, item) {
    var result = _.filter(item.deals, function (c) {
        return c.shop.indexOf('da') != -1;
    });

    if (result.length > 0) {
        var newResult = {};
        newResult.deals = result;
        newResult.id = item.id;
        memo = _.union(memo, newResult);
    }

    return memo;
}, []);