查询返回日期范围中的行但仅返回列的最大值

Question

我想要做的是从表格中选择价格，其中给定的日期在表格中的开始日期和结束日期之间。

SELECT price 
FROM table 
WHERE 'dategiven' BETWEEN startdate AND enddate

使用日期时间过滤器很容易。问题是我在提供的时间窗口中有多个记录，我也有一个版本列。

我的表格下面有一个例子：

我希望我的查询输出如下所示dategiven为2013-08-25

Milk有3条记录，其中2条对dategiven有效（2013-08-25）。然后我想以最高版本返回结果？

类似的东西：

SELECT
    price 
FROM table 
WHERE 'dategiven' BETWEEN startdate AND enddate AND max(version)

Answer 1

使用row_number()函数对行进行排名

select product, price, version
from
(    
    select 
        *, 
        row_number() over (partition by product order by version desc) rn
    from yourtable
    where @dategiven between startdate and enddate
) v
where rn = 1

Answer 2

可能不是最有效的方式，但是：

select price 
 from table 
where 
  'dategiven' between startdate and enddate 
  and version = 
    (
       select max(version) from table t2 where t2.product = table.product
       and 'dategiven' between startdate and enddate 
    )

Answer 3

你也可以尝试这个

select t.product, t.price, version
 from table  t
 inner join
 (select product, max(version) maxVerion from table where
 'dategiven' between startdate and enddate group by product) temp
 on temp.product = t.product and t.version = temp.maxVerion

希望它有所帮助。

Answer 4

我安装的电脑不是sqlservert而是mysql。我不知道它很复杂。

  select t.product, t.price, v.version 
  (
     select temp.product, max(temp.version) as version
     from 
     (
        select product, price, startDate, endDate, version 
        from Table
        where 'dategiven' between startDate and endDate
     ) as temp
     group by temp.product
  ) as v
  inner join Table as t
  on v.version = t.version