Question

我之前尝试过这样的陈述：

public Cursor searchForSchools(String[] args) throws SQLException {
    String myQuery = "SELECT skola._id, skola.naziv, skola.privatna, skola.adresa, opstina.naziv, skola.broj_ucenika, skola.telefon, skola.web, oblast.naziv " +
                    "FROM skola JOIN opstina ON skola.id_opstina = opstina._id " +
                    "JOIN profil ON skola.id_tip = profil._id " +
                    "JOIN oblast_m ON profil._id = oblast_m.id_profil " +
                    "JOIN oblast ON oblast_m.id_oblast = oblast._id ";
    return database.rawQuery(myQuery + "WHERE skola.naziv LIKE \"%?%\" AND opstina.naziv = ? AND skola.broj_ucenika ? AND skola.oblasti LIKE \"%?%\" AND skola.privatna ?", args);

但是由于SQL语法错误，这没有用。

现在，我正在尝试使用以下方法构建子句的第二部分：

public Cursor searchForSchools(String[] args) throws SQLException {
    String myQuery = "SELECT skola._id, skola.naziv, skola.privatna, skola.adresa, opstina.naziv, skola.broj_ucenika, skola.telefon, skola.web, oblast.naziv " +
                    "FROM skola JOIN opstina ON skola.id_opstina = opstina._id " +
                    "JOIN profil ON skola.id_tip = profil._id " +
                    "JOIN oblast_m ON profil._id = oblast_m.id_profil " +
                    "JOIN oblast ON oblast_m.id_oblast = oblast._id ";
    return database.rawQuery(myQuery + buildQueryString(args), null);
}

private String buildQueryString(String[] args) {
    String buildString="WHERE";
    if(args[0]!="*")
        buildString += " skola.naziv LIKE %\"" + args[0] + "\" AND";
    if(args[1]!="*")
        buildString += " opstina.naziv = \"" + args[1] + "\" AND";
    if(args[2]!="*")
        buildString += " skola.broj_ucenika " + args[2] + "\" AND";
    if(args[3]!="*")
        buildString += " oblast.naziv LIKE %\"" + args[3] + "\" AND";
    buildString += " skola.privatna " + args[4];
    return buildString;
}

问题在于，有时args数组包含''（星号），表示查询与该列无关（即任何值都可以接受），但是在第一种调用方法中，像“WHERE opstina.naziv =''”这样的条款会返回错误......

让我解释一下我的目标 - 我想创建一个动态SQL语句，它可以处理返回所有数据的所有情况（当args [] = {''，''时， ''，''，''}}到最复杂的情况，每个args字符串的值都与“”不同。提前谢谢......

使用buildString方法而不是params String数组的SQLite查询

0 个答案: