Question

我在foreach内有一个table，用于加载包含行<tr>的文件。
那个问题是所有的变量都是null并且我已经尝试用加载发送变量，你可以在下一个代码行中看到但是没有成功：

$this->load->view('pedidos/tarefas/tarefa_table', $task);

这是我的表：

<table>
    <thead>
        <tr>
            <th>ID</th>
            <th>Utilizador</th>
            <th>Entidade</th>
            <th>Descrição</th>
            <th>Data Limite</th>
            <th>Estado</th>
            <th>Ações</th>
        </tr>
    </thead>
    <tbody>
        <?php 
            foreach ($tasks as $task) { 

                $this->load->view('pedidos/tarefas/tarefa_table', $task); 

           }
        ?>
    </tbody>
</table>

这是我在load-＆gt;视图中包含的文件：
tarefa_table.php

<tr class="odd gradeX">
    <td><?php print_r($task->id); ?></td>
    <td><?php echo substr($task->user->name, 0, 20); if(intval(strlen($task->user->name)>=20))echo ".."; ?></td>
    <td><?php echo substr($task->entidade->name, 0, 20); if(intval(strlen($task->entidade->name)>=20))echo ".."; ?></td>
    <td><?php echo substr($task->descricao, 0, 30); if(intval(strlen($task->descricao)>=30))echo ".."; ?></td>
    <td style="<?php 
        if ($task->status_id <= 2 || $task->status_id >= 6) {
            if (date('Y-m-d', strtotime($task->data_fim)) == date('Y-m-d')) {
                echo "color: orange";
            } elseif (date('Y-m-d', strtotime($task->data_fim)) < date('Y-m-d')) {
                echo "color: red";
            }else{ 
                echo "color:#274156";  
            }
        } ?>"><?php echo date('d-m-Y', strtotime($task->data_fim)) ?>
    </td>
    <td><?php 
        if($task->status_id <= 2 && date('Y-m-d', strtotime($task->data_fim)) < date('Y-m-d')){
            echo "Atraso";
        }else{
            switch ($task->status_id) {
                case 1: echo "Ativo"; break;
                case 2: echo "Atraso"; break;
                case 3: echo "Pendente"; break;
                case 4: echo "Concluído"; break;
                case 5: echo "Cancelado"; break;
                case 6: echo "Ativo"; break;
                case 7: echo "Atraso"; break;
                default: echo "Não Definido"; break;
        }}?>
    </td>
    <td class="center">                   
        <a href="<?php echo base_url() . 'pedidos/view_task/' . $task->id ?>" title="Ver" class="tip">
            <button class="btn btn-link btn-mini"><span class="icon16 icomoon-icon-eye"></button>
        </a>             
        <a href="<?php echo base_url() . 'pedidos/edit_task/' . $task->id ?>" title="Editar" class="tip">
            <button class="btn btn-link btn-mini"><span class="icon16 icomoon-icon-pencil-5"></button>
        </a>

        <!--<a href="<?php //echo base_url() . 'pedidos/deletetask/' . $task->id ?>" class="confirm-delete tip" title="Apagar">
            <button class="btn btn-link btn-mini"><span class="icon16 typ-icon-trashcan red"></button>
        </a>-->

    </td>
</tr>

Answer 1

为什么不在控制器中加载视图，遍历数据并附加到变量中 $tablecontent并在第一个视图中回显它

//controller

function your_fucntion(){
$tablecontent="";
foreach ($tasks as $task) { 
$tablecontent.=$this->load->view('pedidos/tarefas/tarefa_table', $task,true); 
}
$data['tablecontent']=$tablecontent;
$this->load->view('your view path', $data);
}

 //view
<table>
    <thead>
        <tr>
            <th>ID</th>
            <th>Utilizador</th>
            <th>Entidade</th>
            <th>Descrição</th>
            <th>Data Limite</th>
            <th>Estado</th>
            <th>Ações</th>
        </tr>
    </thead>
    <tbody>
        <?php 
         echo $tablecontent;
        ?>
    </tbody>
</table>

Codeigniter包含文件变量null

1 个答案: