选择Postgres中所有数组中存在的值

Question

我有一些表ignore，其中col ignored_entry_ids包含整数数组。例如：

id     ignored_entry_ids
1      {1,4,6}
2      {6,8,11}
3      {5,6,7}

如何选择阵列中每行中存在的数字？ （考试中有6个）

Answer 1

如果你的数字在数组中是唯一的，你可以做这样的事情，不要认为没有unnest

with cte as (
    select id, unnest(ignored_entry_ids) as arr
    from ign
)
select arr
from cte
group by arr
having count(*) = (select count(*) from ign)

sql fiddle demo

如果数字不唯一，请添加distinct：

with cte as (
    select distinct id, unnest(ignored_entry_ids) as arr
    from ign
)
select arr
from cte
group by arr
having count(*) = (select count(*) from ign)