从两行获取值并转换为变量

时间:2013-08-29 07:26:03

标签: perl sed awk grep

我有两行的值,想要获取所有值并将它们变为变量。

输出来自emc存储:

Bus 0 Enclosure 0  Disk 0
State:                   Enabled

Bus 0 Enclosure 0  Disk 1
State:                   Enabled

预期结果:

Bus:0|Enclosure:0|Disk:0|State:Enabled

或者只是需要有人给我指示如何获得最后一行......

4 个答案:

答案 0 :(得分:3)

这可能适合你(GNU sed):

sed '/^Bus/!d;N;s/[0-9]\+/:&|/g;s/\s//g' file

仅获取最后一行:

sed '/^Bus/{N;h};$!d;x;s/[0-9]\+/:&|/g;s/\s//g' file

答案 1 :(得分:2)

试试这个awk:

$ awk '/^Bus/{for(i=1;i<=NF;i+=2) printf "%s:%s|", $i,$(i+1)}/^State/{printf "%s%s\n", $1, $2}' file
Bus:0|Enclosure:0|Disk:0|State:Enabled
Bus:0|Enclosure:0|Disk:1|State:Enabled

要处理最后一个字段中的多个单词,您可以执行以下操作:

$ awk '/^Bus/{for(i=1;i<=NF;i+=2) printf "%s:%s|", $i,$(i+1)}/^State/{printf "%s", $1; for (i=2;i<=NF;i++) printf "%s ", $i; print ""}' file
Bus:0|Enclosure:0|Disk:0|State:Enabled 
Bus:0|Enclosure:0|Disk:1|State:hot space

答案 2 :(得分:2)

perl -00anE 's/:// for @F; say join "|", map { $_%2 ? () : "$F[$_]:$F[$_+1]" } 0..$#F' file

输出

Bus:0|Enclosure:0|Disk:0|State:Enabled
Bus:0|Enclosure:0|Disk:1|State:Enabled

答案 3 :(得分:1)

使用GNU awk,您可以:

$ awk 'NR>1{$6=$6$7;NF--;print RS,$0}' RS='Bus' OFS='|' file
Bus|0|Enclosure|0|Disk|0|State:Enabled
Bus|0|Enclosure|0|Disk|1|State:Enabled

仅限最后一行:

$ awk 'END{$6=$6$7;NF--;print RS,$0}' RS='Bus' OFS='|' file
Bus|0|Enclosure|0|Disk|1|State:Enabled