我正在学习FIFO并编写了一个迭代服务器来接收来自多个客户端的请求。客户端通过写入服务器的众所周知的fifo来请求文件。服务器从它的FIFO读取并将所请求文件的内容放入客户端读取的新FIFO中。我运行服务器。当我第一次运行客户端时,事情按预期工作,客户端读取文件的内容。当我第二次运行客户端时,来自客户端的消息会以退格符为前缀。我不知道这个退格来自哪里。有任何想法吗? 这是服务器代码:
#include<stdio.h>
#include<string.h>
#include<unistd.h>
#include<errno.h>
#include<sys/types.h>
#include<fcntl.h>
#include<stdlib.h>
#include"fifo.h"
#define SERVFIFO "/tmp/fifo.serv"
#define FILE_MODE (S_IRUSR | S_IWUSR | S_IRGRP | S_IROTH)
int main(int argc, char** argv) {
int readfifo, dummywrite, filefd, writefd, n;
int clientpid;
char buff[MAXLINE], *spaceptr, fifoname[MAXLINE];
if (mkfifo(SERVFIFO, FILE_MODE) < 0 && errno != EEXIST) {
printf("Can't create %s", SERVFIFO);
}
readfifo = open(SERVFIFO, O_RDONLY, 0);
dummywrite = open(SERVFIFO, O_WRONLY, 0);
while ((n = Readline(readfifo, buff, MAXLINE)) > 0) {
printf("Read data from the fifo:%s and the length is:%d and the character is:%d\n", buff, strlen(buff), buff[0]);
if (buff[n - 1] == '\n') {
n--;
printf("I am also omitting the newline\n");
}
buff[n] = '\0';
printf("Buff just after read is:%s and length is %d", buff, strlen(buff));
if ((spaceptr = strchr(buff, ' ')) == NULL) {
printf("Bad request from client");
continue;
}
printf("Found the space:%c\n", *(spaceptr + 1));
*spaceptr++ = '\0';
printf("The value of buffer now is:%s and the length of buffer is:%d and the culprit is %d\n", buff, strlen(buff), *(buff + 0));
clientpid = atol(buff);
printf("The client pid is %ld\n", clientpid);
snprintf(fifoname, sizeof(fifoname), "/tmp/fifoname.%ld", clientpid);
if (mkfifo(fifoname, FILE_MODE) < 0 && errno != EEXIST) {
perror("Can't create the fifo");
continue;
}
printf("Successfully created fifo %s for client\n", fifoname);
if ((writefd = open(fifoname, O_WRONLY, 0)) < 0) {
printf("Cannot open %s", fifoname);
continue;
}
if ((filefd = open(spaceptr, O_RDONLY, 0)) < 0) {
printf("Error opening file\n");
continue;
}
else {
while ((n = read(filefd, buff, MAXLINE))) {
write(writefd, buff, n);
}
close(filefd);
close(writefd);
}
}
}
这是客户端代码:
#include<stdio.h>
#include<string.h>
#include<unistd.h>
#include<errno.h>
#include<sys/types.h>
#include<fcntl.h>
#include<stdlib.h>
#define SERVER_FIFO "/tmp/fifo.serv"
#define MAXLINE 100
#define MSG "%ld sup.c"
#define READFIFO "/tmp/fifoname.%ld"
int main(int argc, char** argv) {
int writefifo, readfifo, n;
char buff[MAXLINE];
pid_t self_pid = getpid();
printf("Started client with PID:%ld\n", self_pid);
writefifo = open(SERVER_FIFO, O_WRONLY, 0);
snprintf(buff, sizeof(buff), MSG, self_pid);
printf("The message to be written to the server is:%s and the length of the message is %d\n", buff, strlen(buff));
if ((n = write(writefifo, buff, sizeof(buff))) != sizeof(buff)) {
perror("Unable to write to server fifo");
exit(0);
}
printf("Message written to the server; Waiting to read contents\n");
snprintf(buff, sizeof(buff), READFIFO, self_pid);
readfifo = open(buff, O_RDONLY, 0);
while ((n = read(readfifo, buff, MAXLINE))) {
write(STDOUT_FILENO, buff, n);
}
close(readfifo);
close(writefifo);
unlink(buff);
}
答案 0 :(得分:2)
也许这是你真实节目的一个切碎版本,因为它没有显示你描述的行为。有几件事:
(1)在服务器
中readfifo = open(SERVFIFO, O_RDONLY, 0);
dummywrite = open(SERVFIFO, O_WRONLY, 0);
我假设你知道,如果你在另一端没有东西的情况下打开着名的fifo,那么open会阻止。这仍然会在O_RONLY上打开,因为在正常情况下,您将在任何客户端之前运行服务器。如果你想避免阻塞只需打开一次读/写。
(2)在客户端
snprintf(buff, sizeof(buff), READFIFO, self_pid);
readfifo = open(buff, O_RDONLY, 0);
这不符合你的想法。您的客户端将消息写入服务器的fifo,服务器使用mkfifo
创建客户端的fifo。由于客户端首先运行,因此当执行此操作时{fif}将不存在open
。实际上,您只是尝试打开一个普通文件(不存在)。您无法读取不存在的文件,因此open
失败,但由于您没有检查打开状态,因此您不知道。
(3)当你完成它们时,取消你的FIFO链接。