我有以下型号:
class Video(models.Model):
name = models.CharField(max_length=200)
pub_date = models.DateTimeField('date published')
filename = models.CharField(max_length=200)
duration = models.IntegerField(default=0)
votes_up = models.IntegerField(default=0)
votes_down = models.IntegerField(default=0)
width = models.IntegerField(default=0)
height = models.IntegerField(default=0)
def __unicode__(self):
return self.name
class Category(models.Model):
name = models.CharField(max_length=200)
def __unicode__(self):
return self.name
class VideoCategory(models.Model):
video = models.ForeignKey('Video')
category = models.ForeignKey('Category')
def __unicode__(self):
return u"{} >> {}".format(self.video.name, self.category.name)
这个观点:
def video_list(request):
if 'category' in request.POST:
#####
else:
video_list = Video.objects.order_by('pub_date')
context = {}
context['videos'] = []
for video in video_list:
video_data = {'name': video.name,
'file': video.filename,
'duration': video.duration,
'resolution': [video.width, video.height],
}
context['videos'].append(video_data)
return HttpResponse(json.dumps(context), content_type="application/json")
一切都按预期工作
现在我想通过类别过滤视频。如何构造如下的查询:
“给我所有的'视频',在'VideoCategory'中有一个条目,'Category'.name就像'xxxxxxx'”
答案 0 :(得分:1)
你可以这样做:
videos = Video.objects.filter(videocategory__category__name='xxxx')
(注意小写模型名称以访问反向关系)
您可以阅读如何查询lookups that span relationships here