我一直在使用下面的代码将VBA模块从一个工作簿压缩到另一个工作簿,我不知道是否有更简单的方法,但它们一直工作正常:
Set srcVba = srcWbk.VBProject
Set srcModule = srcVba.VBComponents(moduleName)
srcModule.Export (path) 'Export from source
trgtVba.VBComponents.Remove VBComponent:=trgtVba.VBComponents.Item(moduleName) 'Remove from target
trgtVba.VBComponents.Import (path) 'Import to target
但是现在我需要复制Sheet中的VBA代码,而不是模块中的VBA代码。上述方法不适用于该场景。
我可以使用哪些代码将工作表中的VBA代码从一个工作簿复制到另一个工作簿?
答案 0 :(得分:28)
您无法删除并重新导入VBComponent
,因为这会从逻辑上删除整个工作表。相反,您必须使用CodeModule
来操作组件中的文本:
Dim src As CodeModule, dest As CodeModule
Set src = ThisWorkbook.VBProject.VBComponents("Sheet1").CodeModule
Set dest = Workbooks("Book3").VBProject.VBComponents("ThisWorkbook") _
.CodeModule
dest.DeleteLines 1, dest.CountOfLines
dest.AddFromString src.Lines(1, src.CountOfLines)
答案 1 :(得分:1)
如果有人在这里寻找VSTO相当于Chel的答案,那么它就是:
void CopyMacros(Workbook src, Workbook dest)
{
var srcModule = src.VBProject.VBComponents.Item(1).CodeModule;
var destModule = dest.VBProject.VBComponents.Add(Microsoft.Vbe.Interop.vbext_ComponentType.vbext_ct_StdModule);
destModule.CodeModule.AddFromString(srcModule.Lines[1, srcModule.CountOfLines]);
}
注意事项:
DeleteLines
。 YMMV。答案 2 :(得分:1)
Patrick的代码不适用于工作表(实际上,它将把代码传送到错误的模块)。一种解决方法是在目标工作簿中创建一个新工作表,然后复制代码(您也可以复制并粘贴工作表的数据/函数/格式)。
其他无效的方法是UserForms。您可以复制代码,但是我不知道有任何方法可以在不使用导出/导入方法的情况下复制实际表单(包括所有控件)。
扩展Patrick的代码:
'Needs reference to : Microsoft Visual Basic for Application Extensibility 5.3 ,
'or run this code : thisworkbook.VBProject.References.AddFromFile "C:\Program Files (x86)\Common Files\Microsoft Shared\VBA\VBA6\VBE6EXT.OLB"
'from immediate window (ctrl+G) or create a small sub
' What works: Successfully tranfsers Modules with code and name
' Copies userform code and name only, but the form is blank (does not transfer controls)
' Copies code in sheets but no content (optionally add code to copy & paste content)
' Successfully transfers Classes with code and name
Option Explicit
Public Sub CopyComponentsModules() 'copies sheets/Thisworkbook/Userforms/Modules/Classes to a new workbook
Dim src As CodeModule, dest As CodeModule
Dim i&
Dim WB_Dest As Workbook
Dim Ref As Reference
Dim Comp As VBComponent
Dim sht As Worksheet
Debug.Print "Starting"
Set WB_Dest = Application.Workbooks.Add
On Error Resume Next 'needed for testing if component already exists in destination WorkBook and for cross-references
For Each Comp In ThisWorkbook.VBProject.VBComponents
Debug.Print Comp.Name & " - "; Comp.Type
Err.Clear
'Set Source code module
Set src = Comp.CodeModule 'ThisWorkbook.VBProject.VBComponents("Sheet1").CodeModule
'Test if destination component exists first
i = 0
i = Len(WB_Dest.VBProject.VBComponents(Comp.Name).Name)
If i <> 0 Then 'or: if err=0 then
Set dest = WB_Dest.VBProject.VBComponents(Comp.Name).CodeModule
Else 'create component
Err.Clear
If Comp.Type = 100 Then
Set sht = WB_Dest.Sheets.Add
Set dest = WB_Dest.VBProject.VBComponents(sht.Name).CodeModule
WB_Dest.VBProject.VBComponents(sht.Name).Name = Comp.Name
sht.Name = Comp.Name
Else
With WB_Dest.VBProject.VBComponents.Add(Comp.Type)
If Err.Number <> 0 Then
MsgBox "Error: Component " & Comp.Name & vbCrLf & Err.Description
Else
.Name = Comp.Name
Set dest = .CodeModule
End If
End With
End If
End If
If Err.Number = 0 Then
'copy module/Form/Sheet/Class 's code:
dest.DeleteLines 1, dest.CountOfLines
dest.AddFromString src.Lines(1, src.CountOfLines)
End If
Next Comp
'Add references as well :
For Each Ref In ThisWorkbook.VBProject.References
WB_Dest.VBProject.References.AddFromFile Ref.FullPath
Next Ref
Err.Clear: On Error GoTo 0
Set Ref = Nothing
Set src = Nothing
Set dest = Nothing
Set Comp = Nothing
Set WB_Dest = Nothing
End Sub
答案 3 :(得分:0)
这是来自不同来源的编译代码以及这一个帖子。 我的贡献是将所有代码从VBE(Sheets / Thisworkbook / Userforms / Modules / Classes)复制到新工作簿的代码。
我创建了这个,因为我有一个损坏的工作簿并制作代码来恢复所有未损坏的代码,包括代码。 (这部分只恢复代码+引用):
'needs a reference to : Visual basic for Application Extensibility 5.3 ,
'or run this code : thisworkbook.VBProject.References.AddFromFile "C:\Program Files (x86)\Common Files\Microsoft Shared\VBA\VBA6\VBE6EXT.OLB"
'from immediate window (ctrl+G) or create a small sub
Option Explicit
Sub CopyComponentsModules() 'copies sheets/Thisworkbook/Userforms/Modules/Classes to a new workbook
Dim src As CodeModule, dest As CodeModule
Dim i&
Dim WB_Dest As Workbook
'Dim sh As Worksheet
Dim Comp As VBComponent
'Set sh = ThisWorkbook.Sheets(1)
'sh.Cells.Clear
Set WB_Dest = Application.Workbooks.Add
On Error Resume Next 'needed for testing if component already exists in destination WorkBook and for cross-references.
For Each Comp In ThisWorkbook.VBProject.VBComponents
'i = i + 1
'sh.Cells(i, 1).Value = Comp.Name
'Set Source code module
Set src = Comp.CodeModule 'ThisWorkbook.VBProject.VBComponents("Sheet1").CodeModule
'test if destination component exists first
i = 0: i = Len(WB_Dest.VBProject.VBComponents(Comp.Name).Name)
If i <> 0 Then 'or: if err=0 then
Set dest = WB_Dest.VBProject.VBComponents(Comp.Name).CodeModule
Else 'create component
With WB_Dest.VBProject.VBComponents.Add(Comp.Type)
.Name = Comp.Name
Set dest = .CodeModule
End With
End If
'copy module/Form/Sheet/Class 's code:
dest.DeleteLines 1, dest.CountOfLines
dest.AddFromString src.Lines(1, src.CountOfLines)
Next Comp
'Add references as well :
Dim Ref As Reference
For Each Ref In ThisWorkbook.VBProject.References
'Debug.Print Ref.Name 'Nom
WB_Dest.VBProject.References.AddFromFile Ref.FullPath
'Debug.Print Ref.FullPath 'Chemin complet
'Debug.Print Ref.Description 'Description de la référence
'Debug.Print Ref.IsBroken 'Indique si la référence est manquante
'Debug.Print Ref.Major & "." & Ref.Minor 'Version
'Debug.Print "---"
Next Ref
Err.Clear: On Error GoTo 0
'WB_Dest.Activate
Set Ref = Nothing
Set src = Nothing
Set dest = Nothing
Set Comp = Nothing
Set WB_Dest = Nothing
End Sub