我正在尝试使用字段代码http://office.microsoft.com/en-us/word-help/field-codes-ref-field-HP005186139.aspx
查找并替换其中的括号和文本Sub replacereftag()
ReplacementText "<test>", "REF Test.Test1 "
End Sub
Private Sub ReplacementText(findtext As String, replacetext As String)
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = findtext
.myrange.Field = replacetext
.Wrap = wdFindContinue
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
答案 0 :(得分:0)
在我看来,你需要在代码中使用不同类型的逻辑。主要区别在于您需要先找到您的文本并选择它。下一步,您需要在选择范围内添加一个字段。以下子程序改进了你做这些事情的人。希望这是你在寻找的。 (见代码中的一些评论)
Sub replacereftag()
ReplacementText "<test>", "REF Test.Test1 "
'if you keep .MatchWildcards = True below then call next sub in this way:
'ReplacementText "\<test\>", "REF Test.Test1 "
End Sub
Private Sub ReplacementText(findtext As String, replacetext As String)
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = findtext
'I removed something here
.Wrap = wdFindContinue
.MatchWildcards = False '!!!- both <> are special characters!!
End With
'looping to search for all occurrences
Do While Selection.Find.Execute
'add a field here
Selection.Fields.Add Range:=Selection.Range, Type:=wdFieldEmpty, Text:= _
"REF Test.Test1", PreserveFormatting:=False
Loop
End Sub
修改
Sub replacereftag()
ReplacementText "<test>", "REF Test.Test"
Dim i
for i=1 to 10 'change to last number
ReplacementText "<test" & i & ">", "REF Test.Test" & i
next i
End Sub