Question

我在GAE中有一些servlet，来自Android应用程序;我想从其中一个servlet发送一个POST请求到使用xampp在localhost中托管的php。尝试读取响应时，servlet达到IOException。

这是我正在使用的示例servlet的代码：

protected void doPost(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException {

    String result = "";

    try {
        URL url = new URL("http://172.25.3.50:80/tempofinito/prueba.php");
        HttpURLConnection con = (HttpURLConnection) url.openConnection();
        con.setRequestMethod("POST");
        con.setDoOutput(true);
        con.setDoInput(true);

        // Send         
        DataOutputStream wr = new DataOutputStream (
                  con.getOutputStream ());
        wr.writeBytes ("prueba=" + URLEncoder.encode("message","UTF-8"));
        wr.flush ();
        wr.close ();

        // Response
        InputStream is = con.getInputStream();
        BufferedReader rd = new BufferedReader(new InputStreamReader(is));
        String line;
        StringBuffer resp = new StringBuffer(); 
        while((line = rd.readLine()) != null) {
          resp.append(line);
          resp.append('\r');
        }
        rd.close();
        result =  resp.toString();

    } catch (MalformedURLException e) {
        result = "malformed";
    } catch (IOException e) {
        result = "ioexception";
    }

    // Sends result to Android APP
    PrintWriter out = response.getWriter();
    out.println(result);
}

这是php文件：

<?php
$variable = $_POST["prueba"];
echo "ESTO ES UNA PRUEBA ".$variable;
?>

这是Android代码：

new AsyncTask<Void, Void, String>() {
        protected String doInBackground(Void... params) {   

            HttpClient client = new DefaultHttpClient();
            HttpPost postMethod = new HttpPost(Globals.serverURL + "/prueba");
            String result = "";

            try {
                // Ignore this ->
                ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(3);
                nameValuePairs.add(new BasicNameValuePair("UserName", Globals.user));
                nameValuePairs.add(new BasicNameValuePair("Pass", Globals.encrypt(Globals.pass)));
                nameValuePairs.add(new BasicNameValuePair("Mode", "user"));
                // <-

                postMethod.setEntity(new UrlEncodedFormEntity(nameValuePairs));
                HttpResponse response = client.execute(postMethod);

                HttpEntity entity = response.getEntity();

                result = EntityUtils.toString(entity);                  
            } catch (ClientProtocolException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }

            return result;
        }

因此，APP调用servlet“prueba”。此servlet只是尝试向php文件发送POST请求，但在“// Response”部分中达到IOException。我想我做错了，因为如果我从servlet复制相同的代码并将其粘贴到Android APP中，而不是上面的代码，它可以正常工作。

我应该在Google App Engine中以不同的方式进行此操作吗？

Answer 1

这是阻止连接的防火墙的一个愚蠢问题。

从谷歌应用引擎发送邮件请求到PHP

1 个答案: