我有一份登记表。在这里,我可以通过我的自定义检查重复的电子邮件是唯一的回调函数(不要尝试使用is_unique)。但它不会返回任何东西。这是我的代码。
控制器 -
public function add_member () {
$this->load->library('form_validation');
$post_email = $this->input->post('email_id');
$this->form_validation->set_rules('email_id', 'Email ID/ Username', 'required|trim|xss_clean|valid_email|callback_check_duplicate_email[' . $post_email . ']');
$this->form_validation->set_rules('password', 'Your password', 'required|min_length[5]|max_length[12]|matches[confirm_password');
$this->form_validation->set_rules('confirm_password', 'Password Confirmation', 'required');
$this->form_validation->set_message('check_duplicate_email', 'This email is already exist. Please write a new email.');
if ($this->form_validation->run() == FALSE) {
// validation failed then do that
$this->load->view('member/reg_form');
} else {
$data['email_id'] = $post_email;
$data['password'] = MD5($this->input->post('password'));
$insert = $this->Model_member->insert_data_to_db($data);
if ($insert) {
$success = "Wao ! You are successfully added to our community.";
$this->session->set_flashdata('message_success', $success);
$this->load->view('member/success_page');
} else {
$error = "Hey this email is already exists in our community.";
$this->session->set_flashdata('message_error', $error);
$this->load->view('member/reg_form');
}
}
}
// My callback function
public function check_duplicate_email($post_email) {
return $this->Model_member->checkDuplicateEmail($post_email);
}
模型 -
//for checking email existance
public function checkDuplicateEmail($post_email) {
$this->db->where('email_id', $email_id);
$query = $this->db->get('my_registration_table');
$count_row = $query->num_rows();
if ($count_row > 0) {
return TRUE;
} else {
return FALSE;
}
}
// insert data to DB
public function insert_data_to_db($data) {
return $this->db->insert('my_registration_table', $data);
}
当我尝试使用已存在的电子邮件提交表单时。此功能不会阻止我,也不会显示验证错误消息。有谁会在这里看到有什么问题?等待你的帮助。
答案 0 :(得分:6)
您的问题出在模型功能中。看看下面的模型函数。
public function checkDuplicateEmail($post_email) {
$this->db->where('email_id', $email_id);
$query = $this->db->get('my_registration_table');
$count_row = $query->num_rows();
if ($count_row > 0) {
//if count row return any row; that means you have already this email address in the database. so you must set false in this sense.
return FALSE; // here I change TRUE to false.
} else {
// doesn't return any row means database doesn't have this email
return TRUE; // And here false to TRUE
}
}
试试这个。希望有效。
答案 1 :(得分:0)
如果我没弄错的话,那个功能应该在控制器中,而不是在模型中。
答案 2 :(得分:0)
Call the right method in your model, as you defined in your controller.And your variable name should be same as argument passed in your function.I think it works.
Model:
public function insert_data_to_db($post_email) {
$this->db->where('email_id', $post_email);
$query = $this->db->get('my_registration_table');
$count_row = $query->num_rows();
if ($count_row > 0) {
return TRUE;
} else {
return FALSE;
}
}
答案 3 :(得分:0)
您标记为正确的答案是正确的,但最终会遇到逻辑错误。
您传入了在$ post_email中保存的电子邮件ID,但是codeigniter允许您传入正在修剪,清理等的变量。
因此,既然您按原样保存了帖子数据的副本,如果有空格或其他应修剪的内容不是,但修剪后的版本是匹配的,那么它就不会匹配
换句话说: " me@my.com"可能不匹配" me@my.com"通过验证,然后存储2份" me@my.com"。
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