Question

我有以下代码行给出了错误：

rescue Timeout::Error => e
    logs.puts("Rescued a timeout error...#{e}")
    email_ids_all.each do |email_delete|

      call= "/api/v2/emails/#{email_delete}/"
      uri= HTTParty.delete("https://www.surveys.com#{call}",
          :basic_auth => auth,
          :headers => { 'ContentType' => 'application/x-www-form-urlencoded', 'Content-Length' => "0" }
      )
      puts "Deleted email #{email_delete}".green
      log.puts("Deleted email #{email_delete}")
    end
    abort #abort entire script after deleting emails
  end

我收到的错误是：

syntax error, unexpected keyword_rescue, expecting $end
  rescue Timeout::Error => e
        ^

基本上我只是在脚本超时的情况下尝试运行API删除调用。虽然我在rescue的块中放入了什么并不重要，但是我收到了同样的错误。我在rescue方法上的语法有什么问题？

Answer 1

使用rescue的格式如下：

begin
  # Code you want to run that might raise exceptions
rescue YourExceptionClass => e
  # Code that runs in the case of YourExceptionClass
rescue ADifferentError => e
  # Code that runs in the case of ADifferentError
else
  # Code that runs if there was no error
ensure
  # Code that always runs at the end regardless of whether or not there was an error
end

以下是一个包含更多信息的问题：Begin, Rescue and Ensure in Ruby?。

Ruby救援语法错误

1 个答案: