Question

我有一个带有一些值的数组。如何使用jQuery搜索该数组以获得与其匹配或接近的值？

var a = ["foo","fool","cool","god","acl"];

如果我想搜索c，则应该返回cool而不是acl。

我如何实现这一目标？

Answer 1

试试这个： -

arr = jQuery.grep(a, function (value) {
    search = /c/gi;
    if(value.match(search)) return true;
        return false;
    });

或

function find(arr) {
    var result = [];

    for (var i in arr) {
        if (arr[i].match(/c/)) {
            result.push(arr[i]);
        }
    }

    return result;
}

window.onload = function() {
    console.log(find(["foo","fool","cool","god","acl"]));
};

Answer 2

使用substring检查数组中的每个字符串是否以您要搜索的字符串开头：

var strings = [ "foo", "cool", "acl" ];
var needle = "c";

for (var i = 0; i < strings.length; ++i) {
    if (strings[i].substring(0, needle.length) === needle) {
        alert("found: " + strings[i]);
    }
}

Answer 3

一种简单的方法是检查以'c'开头的单词并迭代数组。

var ar = ['acl','cool','cat']
for(var i = 0 ; i<ar.length ; i++){
   console.log(ar[i].match(/^c/))
}
//Prints:
//null
//["c", index: 0, input: "cool"]
//["c", index: 0, input: "cat"]

Answer 4

您可以使用自JavaScript 1.6以来可用的过滤方法。它会返回一个包含过滤值的数组。如果你想匹配多个项目，非常方便。

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter

var a = ["foo","fool","cool","god","acl"];
var startsWith = 'c';

a.filter(function (value) {
    return value && value.length > 0 && value[0] == startsWith;
});

// yields: ["cool"]

Answer 5

var a = ["foo","fool","cool","god","acl"];
var Character="f";
for(i=0;i<a.length;i++){
    if(a[i].indexOf(Character)!=-1){

        document.write(a[i]+"<br/>");
    }
 }

如何在Jquery中搜索数组，如SQL LIKE值％语句

5 个答案: