Question

I have actually this code for an embedded application. I am 1st trying to make it for plain c++ so that I may have concept clear。

我为每个英文字母分配了一个数字代码。我希望我的程序输出一个句子的等效数字代码。实际上，循环应该为句子的每个数字迭代次数。我需要为每个数字的嵌入式应用程序打开/关闭引脚。我必须在相同字母的数字之间，两个字母之间添加时差，＆amp;之后两句话之间。第一，我希望得到的代码的每个数字都是纯输出。

这是我的代码。我已经为String＆amp;分配了字母表。代码为String数组类型。然后我从String array＆amp;中搜索字符的等效数字代码。将其保存为字符串类型。现在我想将每个数字从字符串分配给int＆amp;为它循环。但是我在将字符串值赋给int时遇到了麻烦。我没有太多的C ++编程经验。

修改我在第一个地方将字符串转换为int时遇到了麻烦，＆amp;总的来说这个解决我问题的逻辑似乎很好。

这是我的代码，这就是我试图解决我的问题的方法。

    #include <iostream>
    #include <string>
    using namespace std;


        string texttopattern(char c)
        {

    //Hello world again
    //125-15-123-123-135 1346-135-1235-123-145 1-1245-1-24-1345

        string alphabet = "abcdefghijklmnopqrstuvwqyz"; //osv
        string code[] = {"1","12","14","145", "15", "124", "1245",
                          "125", "24", "245", "13", "123", "134",
                          "1345", "135", "1234", "12345", "1235", "234", "2345",
                          "136", "1236", "1346", "13456", "1356", "12346"};
          int index = alphabet.find(c);
            if(index!=-1)
                return code[index];
             else
                return " ";
        }

int main()
{
    string ord;
    getline(cin, ord);
    string code="";
        for(int i=0; i<ord.length(); i++)
        {
        code += texttopattern(ord[i]);
        }

        for(int i=0; i<code.length(); i++) {
            int n = code[i]; //assign a single digit value from string to an   
                             //int,string2int assign value is problem here !!
              while(n>0){    //loop for n times & manipulate PIN in each iteration
                cout<<"loop";
                n--;      }
        //cout<<code[i]<<endl;
        }

        return 0;
}

Answer 1

我认为你不应该使用名为int的变量，它是C ++和C中的关键字。

所以至少你在while循环上有错误。将while循环更改为

       int j = code[i] - '0'; // this will get the number from the char 
       while(j>0){
           cout<<"loop";
           --j;      
       }

Answer 2

编辑：为了回应你的评论，我现在又回到了使用字符串作为模式：

#define UNKNOWN_LETTER_PATTERN ""

string texttopattern(char c)
{
    string code[] = {"1","12","14","145", "15", "124", "1245",
                      "125", "24", "245", "13", "123", "134",
                      "1345", "135", "1234", "12345", "1235", "234", "2345",
                      "136", "1236", "1346", "13456", "1356", "12346"};
    if (c >= 'a' && c <= 'z')
        return code[c - 'a'];
    else
        return UNKNOWN_LETTER_PATTERN ;
}

main()的第一部分保持不变：

int main()
{
    string ord;
    getline(cin, ord);
    vector<string> code;
    for(int i=0; i<ord.length(); i++)
    {
        code.push_back(texttopattern(ord[i]));
    }

更新了其余部分并添加了一些评论，希望能够解释我在做什么：

    // Loop patterns
    for (vector<string>::iterator it = code.begin(); it != code.end(); it++) 
    {
        if (*it == UNKNOWN_LETTER_PATTERN )
        {
            // Don't know what to do with unknown chars like spaces - your problem
            cout << "unknown letter" << endl;
        }
        else
        {
            // Loop every digit in the current  pattern
            for (int i = 0; i < it->size(); i++)
            {
                char c = it->at(i);

                // There surely is a better way to do the following, atoi or
                // stringstream come to mind
                // But for a single digit number, this should be enough for
                // now to convert a char to a number.
                int number = c - '0'; 

                // loop until number is reached
                for (int j = 0; j < number; j++)
                    cout << "I";
                cout << endl;
            }
            cout << "End of letter" << endl;
        }
    }

    cin.get();

    return 0;
}

编辑：我更改了上面的示例。它现在的作用是，例如：输入是'd' - ＆gt;解析代码“145” - ＆gt;循环每个数字并转到数字[1,4,5] - ＆gt;为每个数字“I IIII IIIII”打印'I'数字次。重读评论后，我相信这就是你想要的。

Answer 3

我真的希望我理解你的意思。我试图制作一个你在这里展示的程序，我想出了这个：

Macros.h：

#ifndef MY_MACROS_H
#define MY_MACROS_H

#define VALUES(base)                \
                ADD_VALUE(0,base)   \
                ADD_VALUE(1,base)   \
                ADD_VALUE(2,base)   \
                ADD_VALUE(3,base)   \
                ADD_VALUE(4,base)   \
                ADD_VALUE(5,base)   \
                ADD_VALUE(6,base)   \
                ADD_VALUE(7,base)   \
                ADD_VALUE(8,base)   \
                VALUE(9,base)

#define VALUE(val,base) +1

#define ADD_VALUE(val,base) VALUE(val, base)


#define DIGIT_COUNT (0 VALUES(1))
#define BASE_COUNT  (DIGIT_COUNT + 1)

#define ALL_VALUES   ADD_ARRAY_VALUES(1)                                  \
                     ADD_ARRAY_VALUES(BASE_COUNT)                         \
                     ADD_ARRAY_VALUES(BASE_COUNT * BASE_COUNT)            \
                     ARRAY_VALUES(BASE_COUNT * BASE_COUNT * BASE_COUNT)

#define ARRAY_VALUES(rank) +1

#define ADD_ARRAY_VALUES(rank) ARRAY_VALUES(rank)

#define UNKNOWN_LETTER_PATTERN ""
#define ARRAYS_COUNT (0 ALL_VALUES)

#endif

Header.h：

    #ifndef _MY_HEADER_H
#define _MY_HEADER_H

/*****
* Includes
******/
#include <iostream>
#include <string>
#include <vector>
#include "Macros.h"

using namespace std;

/*****
* Definitions
******/
#define FIRST_LETTER 'a'
#define LAST_LETTER  'z'

typedef unsigned char byte;

typedef int NumberValueType;

#define BASE_CHAR_VALUE '0'

// character 
#define CHAR_TO_CHAR_INDEX(character) (character - FIRST_LETTER) 
#define CHAR_TO_NUM_INDEX(character)  (character - BASE_CHAR_VALUE)

#define IS_CHAR_VALID(character) ((character >= FIRST_LETTER) && (character <= LAST_LETTER))

int ParseInput();
string texttopattern(char c);

#endif

实施文件:(当然我也打印过，并没有对输出做过任何重要的事情）。

Main.cpp的：

    #include "Header.h"

int s_arValues[ARRAYS_COUNT][DIGIT_COUNT] =
{   
    #undef  VALUE
    #define VALUE(val,base) (base * val)

    #undef ADD_VALUE
    #define ADD_VALUE(val,base) VALUE(val, base),

    #undef ARRAY_VALUES
    #define ARRAY_VALUES(rank) { VALUES(rank) }

    #undef ADD_ARRAY_VALUES
    #define ADD_ARRAY_VALUES(rank) ARRAY_VALUES(rank),

    ALL_VALUES
};


string texttopattern(char c)
{
    string code[] = {"1","12","14","145", "15", "124", "1245",
                      "125", "24", "245", "13", "123", "134",
                      "1345", "135", "1234", "12345", "1235", "234", "2345",
                      "136", "1236", "1346", "13456", "1356", "12346"};
    if (IS_CHAR_VALID(c))
        return code[CHAR_TO_CHAR_INDEX(c)];
    else
        return UNKNOWN_LETTER_PATTERN ;
}

int ParseInput()
{
    string ord;
    getline(cin, ord);
    vector<string> code;

    for(int i=0; i<ord.length(); i++)
    {
        code.push_back(texttopattern(tolower(ord[i])));
    }

    // Loop inputs
    for (vector<string>::iterator itInputs = code.begin(); itInputs != code.end(); itInputs++) 
    {
        if (*itInputs == UNKNOWN_LETTER_PATTERN)
        {
            // Don't know what to do with unknown chars like spaces - your problem
            cout << "unknown letter" << endl;
            continue;
        }

        int number = 0;
        int nInputSize = itInputs->size();

        // Loop every digit in the current pattern
        for (int nDigitIndex = 0; nDigitIndex < nInputSize; nDigitIndex++)
        {
            if(nDigitIndex >= sizeof(NumberValueType))
            {
                cout << number;
                number = 0;
                continue;
            }

            char cChar = itInputs->at(nDigitIndex);

            number += s_arValues[nInputSize - nDigitIndex - 1][CHAR_TO_NUM_INDEX(cChar)]; 
        }

        // At this point you can use number
        cout << number;
        cout << endl;
        cout << "End of letter" << endl;
    }

    cin.get();

    return 0;
}

void main()
{   
    ParseInput();
}

Answer 4

以下是我如何解决问题的代码。感谢所有回复的人，虽然一些回复对我来说太复杂了。请看它＆amp;通过我正在寻找的输出来指出任何缺点。

#include <iostream>
#include <string>
#include <sstream>
using namespace std;

 string texttopattern(char c)
    {

//Hello world again
//125-15-123-123-135 1346-135-1235-123-145 1-1245-1-24-1345

    string alphabet = "abcdefghijklmnopqrstuvwqyz"; //osv
    string code[] = {"1","12","14","145", "15", "124", "1245",
                      "125", "24", "245", "13", "123", "134",
                      "1345", "135", "1234", "12345", "1235", "234", "2345",
                      "136", "1236", "1346", "13456", "1356", "12346"};
      int index = alphabet.find(c);
        if(index!=-1)
            return code[index];
         else
            return " ";
    }

int main()
{
    int n;
    string ord;
    getline(cin, ord);
    string code="";
        for(int i=0; i<ord.length(); i++)
        {
        code += texttopattern(ord[i]);
        }

         for(int i = 0; i<code.length(); i++){
              n = code[i] - '0';
                for(int i=0; i<n; i++){
                  cout<<"Here you go"<<"-"<<n<<endl;}}

        return 0;
        }

C ++字母表等效数字代码输出程序

4 个答案: