我正在尝试从属性读取的文件路径中读取文件,但我一直收到FileNotFoundException(文件存在)。
test.properties:
test.value = "src/main/resources/File.csv"
LoadProperties.java:
public class LoadProperties {
public static void main(String[] args) throws FileNotFoundException, IOException {
Properties aProp = new Properties();
aProp.load(new FileInputStream("src/main/resources/test.properties")); // works
String filepath = aProp.getProperty("test.value");
System.out.println(filepath); // outputs: "src/main/resources/File.csv"
FileReader aReader = new FileReader("src/main/resources/File.csv"); // works
FileReader aReader2 = new FileReader(filepath); // java.io.FileNotFoundException
}
}
为什么在它上面的行正常工作时抛出这个异常? 我应该如何从提供属性的路径中读取文件?
答案 0 :(得分:3)
你不应该把“放在你的属性文件中。这里Java认为它是:
String file = "\"src/main/resources/File.csv\"";
答案 1 :(得分:1)
test.value =src/main/resources/File.csv
属性文件中不需要双引号来表示连续字符串。
答案 2 :(得分:0)
你可以编写自己的逻辑来读取属性文件,文件路径中是否有单引号或双引号无关紧要
String propertyFileLocation = "C:\a\b\c\abc.properties";
try
{
fileInputStream = new FileInputStream(propertyFileLocation);
bufferedReader = new BufferedReader(new InputStreamReader(fileInputStream));
properties = new Properties();
String currentLine = null;
String[] keyValueArray = null;
while ((currentLine = bufferedReader.readLine()) != null) {
if (!currentLine.trim().startsWith("#")) {
keyValueArray = currentLine.split("=");
if (keyValueArray.length > 1) {
properties.put(keyValueArray[0].trim(), keyValueArray[1].trim().replace("\\\\","\\"));
}
}
}
}
catch (Exception e)
{
return null;
}