Volley没有为我的自定义请求调用getParams?

时间:2013-08-28 09:52:35

标签: android get android-volley

请问,Volley会自动将我的GET参数添加到URL吗?对我而言,它不是这样的,而且在查看源代码时,我无法找到任何getParams方法的调用。 我应该自己构建URL吗?这根本不是问题,我只是认为当有像getParams这样的方法时,它可以为我做到这一点:)

更新:以下是我的代码..

public class BundleRequest extends com.android.volley.Request<Bundle>{

    private String token;
    private OnAuthTokenValidatorResponseListener mListener;
    private final Map<String, String> mParams =  new HashMap<String, String>();;


    public BundleRequest(int method, String url,  Response.ErrorListener listener) {
        super(method, url, listener);
    }

    public BundleRequest(int method, String url,OnAuthTokenValidatorResponseListener providedListener,  Response.ErrorListener listener, String token) {
        super(method, url, listener);
        this.token = token;
        mListener = providedListener;
        mParams.put(AuthenticatorConfig.TOKEN_VALIDATION_PARAMNAME, token);

    }

    @Override
    public Map<String, String> getParams() throws AuthFailureError {
        return mParams;
    }




    @Override
    protected Response<Bundle> parseNetworkResponse(NetworkResponse httpResponse) {
        switch (httpResponse.statusCode) {
            case AuthTokenValidator.TOKEN_VALID_RESPONSE_CODE:
                //token is ok
                JSONObject response;
                try {
                        response = new JSONObject(new String(httpResponse.data, HttpHeaderParser.parseCharset(httpResponse.headers)));
                        Bundle userDataResponse = new Bundle();
                        userDataResponse.putInt("responseCode", httpResponse.statusCode);
                        userDataResponse.putString("username", response.getString("user_id"));
                        userDataResponse.putString("email", response.getString("user_email"));
                        userDataResponse.putString("expiresIn", response.getString("expires_in"));
                        userDataResponse.putString("scope", response.getJSONArray("scope").getString(0));
                        userDataResponse.putString("token", token);
                    return Response.success(userDataResponse, HttpHeaderParser.parseCacheHeaders(httpResponse));
                    } catch (UnsupportedEncodingException e) {
                        e.printStackTrace();
                    return Response.error(new VolleyError("Unsupported encoding"));


                } catch (JSONException e) {
                    e.printStackTrace();
                    return Response.error(new VolleyError("Problem while parsing JSON"));
                }




            case AuthTokenValidator.TOKEN_INVALID_RESPONSE_CODE:
                //token is not valid
                mListener.onValidatorResponse(httpResponse.statusCode);
                try {
                    mListener.onValidatorResponse(parseOnErrorResponse(new String(httpResponse.data, HttpHeaderParser.parseCharset(httpResponse.headers))));
                } catch (UnsupportedEncodingException e) {
                    e.printStackTrace();
                }

            default:
                return Response.error(new VolleyError("Error status code:" + httpResponse.statusCode));

        }
    }

    protected int parseOnErrorResponse(String responseBody) {
        try {
            JSONObject response = new JSONObject(responseBody);
            String moreInfo = response.getString("more_info");
            if (moreInfo.equals("Token was not recognised")) {
                return AuthTokenValidator.TOKEN_WAS_NOT_RECOGNISED;
            } else if (moreInfo.equals("Token has expired")) {
                return AuthTokenValidator.TOKEN_HAS_EXPIRED;
            } else if (moreInfo.equals("Client doesn't exist anymore")) {
                return AuthTokenValidator.CLIENT_DOES_NOT_EXIST_ANYMORE;
            } else if (moreInfo.equals("Client is locked")) {
                return AuthTokenValidator.CLIENT_IS_LOCKED;
            } else {
                return AuthTokenValidator.UNKNOWN_ERROR;
            }

        } catch (JSONException e) {
            e.printStackTrace();
            return AuthTokenValidator.UNKNOWN_ERROR;
        }

    }

    @Override
    protected void deliverResponse(Bundle response) {
        mListener.onGetUserDataResponse(response);
    }
}

实际上params参数现在是多余的

3 个答案:

答案 0 :(得分:10)

GET方法未调用

getParams(),因此您似乎必须在发送请求之前将其添加到URL中。

查看JavaDoc:

  

返回用于POST或PUT请求的参数Map。

     

可以抛出{@link AuthFailureError},因为可能需要进行身份验证   提供这些价值观。

     

请注意,您可以直接覆盖{@link #getBody()}以进行自定义   数据

     

在auth失败的情况下@throws AuthFailureError

答案 1 :(得分:1)

关于Itai Hanski回答,这是实现这一点的一个例子:

 for(String key: params.keySet()) {
   url += "&"+key+"="+params.get(key);
 }

答案 2 :(得分:0)

试试这个,

public class LoginRequest extends Request<String> {

    // ... other methods go here

    private Map<String, String> mParams;

    public LoginRequest(String param1, String param2, Listener<String> listener, ErrorListener errorListener) {
        super(Method.POST, "http://test.url", errorListener);
        mListener = listener;
        mParams.put("paramOne", param1);
        mParams.put("paramTwo", param2);

    }

    @Override
    public Map<String, String> getParams() {
        return mParams;
    }
}

也见这个例子,

https://github.com/evancharlton/folly/