如果我在页面中有10个数据= 1在分页中,另一个页面具有ie = 2有另外10个数据。在该页面= 3之后不包含任何数据。如果我选择上一个按钮然后该页面进入page-1,page = -2 .....如果我按下一个按钮,它也将继续像page = 2,page = 3等等。如果记录为no,如何禁用prev和next按钮更长时间?
<?php
include("config.php");
$start = 0;
$per_page = 5;
if(!isset($_GET['page'])){
$page = 1;
} else{
$page = $_GET['page'];
}
if($page<=1)
$start = 0;
else
$start = $page * $per_page - $per_page;
$sql="select id,question,correctAnswer,category from math order by id";
$num_rows = mysql_num_rows(mysql_query($sql));
$num_pages = $num_rows / $per_page;
$sql .= " LIMIT $start, $per_page";
$result=mysql_query($sql) or die(mysql_error());
while($row=mysql_fetch_array($result))
{ ?>
.......
........
<?php
$prev = $page - 1;
$next = $page + 1;
echo "<a href='?page=$prev'>prev</a> ";
echo " <a href='?page=$next'>next</a> ";
?>
答案 0 :(得分:2)
这个怎么样:
<?php
include("config.php");
$start = 0;
$per_page = 5;
if(!isset($_GET['page'])){
$page = 1;
} else{
$page = $_GET['page'];
}
if($page<=1)
$start = 0;
else
$start = $page * $per_page - $per_page;
$sql="select id,question,correctAnswer,category from math order by id";
$num_rows = mysql_num_rows(mysql_query($sql));
$num_pages = $num_rows / $per_page;
$sql .= " LIMIT $start, $per_page";
$result=mysql_query($sql) or die(mysql_error());
while($row=mysql_fetch_array($result))
{ ?>
.......
........
<?php
if($page > 1){
$prev = $page - 1;
$prev = " <a href='?page=$prev'>prev</a> ";
} else {
$prev = "";
}
if($page < $num_pages){
$next = $page + 1;
$next = " <a href='?page=$next'>next</a> ";
}
echo $prev;
echo $next;
?>
答案 1 :(得分:1)
使用以下代码:
<?php
include("config.php");
$start = 0;
$per_page = 5;
if(!isset($_GET['page'])){
$page = 1;
} else{
$page = $_GET['page'];
}
if($page<=1)
$start = 0;
else
/*add these lines*/
$cnt=mysql_query("select count(*) as ct from math") or die(mysql_error());
$data=mysql_fetch_array($cnt);
$total = $data['ct'];
$start = $page * $per_page - $per_page;
$sql="select id,question,correctAnswer,category from math order by id";
$num_rows = mysql_num_rows(mysql_query($sql));
$num_pages = $num_rows / $per_page;
$sql .= " LIMIT $start, $per_page";
$result=mysql_query($sql) or die(mysql_error());
while($row=mysql_fetch_array($result))
{ ?>
.......
........
<?php
$prev = $page - 1;
$next = $page + 1;
/*also add these condition*/
if($page > 1)
echo "<a href='?page=$prev'>prev</a> ";
/*also add these condition*/
if($total > ($page*$per_page))
echo " <a href='?page=$next'>next</a> ";
?>
注意:始终使用PDO或mysqli_ *,因为不推荐使用mysql_ * 最新的PHP版本。这将是未来的良好实践。
答案 2 :(得分:0)
试试这个:
<?php
include("config.php");
$per_page = 5;
$page = (is_numeric($_GET['page']) ? $_GET['page'] : 0);
$sql = "SELECT `id`,`question`,`correctAnswer`,`category` FROM `math` ORDER BY `id`";
$num_rows = mysql_num_rows(mysql_query($sql));
$num_pages = ceil($num_rows / $per_page);
$sql .= " LIMIT ".$per_page*$page.", {$per_page}";
$result=mysql_query($sql) or die(mysql_error());
while ($row=mysql_fetch_array($result)) { ?>
.......
........
<?php
$prev = $page - 1;
$next = $page + 1;
echo "<a href='?page=$prev'>prev</a> ";
echo " <a href='?page=$next'>next</a> ";
?>