将LaTeX转换为动态Javascript函数

时间:2013-08-28 01:24:02

标签: javascript latex

我有一个方程式的用户输入 - 这个输入使用一个我没有编码的单独的API生成LaTeX代码(即Mathquill,并不重要)。

我的问题最好通过一个例子说明:假设从用户输入生成的LaTeX代码是这样的:

x^2+3x-10sin\left(2x\right) 

我如何将此(当然是动态)转换为JavaScript函数,硬编码的函数如下所示:

function(x) {
  return Math.pow(x, 2) + 3 * x - 10 * Math.sin(2 * x);
}

是否有任何API或者我正在寻找能够解释LaTeX符号并以某种方式创建函数的东西?或者是什么?

3 个答案:

答案 0 :(得分:4)

我写了一个(绝不是通用的)解决方案,很大程度上基于乔治的代码。

这是:

var CALC_CONST = {
  // define your constants
  e: Math.E,
  pi: Math.PI
};

var CALC_NUMARGS = [
  [/^(\^|\*|\/|\+|\-)$/, 2],
  [/^(floor|ceil|(sin|cos|tan|sec|csc|cot)h?)$/, 1]
];

var Calc = function(expr, infix) {
  this.valid = true;
  this.expr = expr;

  if (!infix) {
    // by default treat expr as raw latex
    this.expr = this.latexToInfix(expr);
  }

  var OpPrecedence = function(op) {
    if (typeof op == "undefined") return 0;

    return op.match(/^(floor|ceil|(sin|cos|tan|sec|csc|cot)h?)$/) ? 10

         : (op === "^") ? 9
         : (op === "*" || op === "/") ? 8
         : (op === "+" || op === "-") ? 7

         : 0;
  }

  var OpAssociativity = function(op) {
    return op.match(/^(floor|ceil|(sin|cos|tan|sec|csc|cot)h?)$/) ? "R" : "L";
  }

  var numArgs = function(op) {
    for (var i = 0; i < CALC_NUMARGS.length; i++) {
      if (CALC_NUMARGS[i][0].test(op)) return CALC_NUMARGS[i][1];
    }
    return false;
  }

  this.rpn_expr = [];
  var rpn_expr = this.rpn_expr;

  this.expr = this.expr.replace(/\s+/g, "");

  // This nice long regex matches any valid token in a user
  // supplied expression (e.g. an operator, a constant or
  // a variable)
  var in_tokens = this.expr.match(/(\^|\*|\/|\+|\-|\(|\)|[a-zA-Z0-9\.]+)/gi);
  var op_stack = [];

  in_tokens.forEach(function(token) {
    if (/^[a-zA-Z]$/.test(token)) {
      if (CALC_CONST.hasOwnProperty(token)) {
        // Constant. Pushes a value onto the stack.
        rpn_expr.push(["num", CALC_CONST[token]]);
      }
      else {
        // Variables (i.e. x as in f(x))
        rpn_expr.push(["var", token]);
      }
    }
    else {
      var numVal = parseFloat(token);
      if (!isNaN(numVal)) {
        // Number - push onto the stack
        rpn_expr.push(["num", numVal]);
      }
      else if (token === ")") {
        // Pop tokens off the op_stack onto the rpn_expr until we reach the matching (
        while (op_stack[op_stack.length - 1] !== "(") {
          rpn_expr.push([numArgs(op_stack[op_stack.length - 1]), op_stack.pop()]);
          if (op_stack.length === 0) {
            this.valid = false;
            return;
          }
        }

        // remove the (
        op_stack.pop();
      }
      else if (token === "(") {
        op_stack.push(token);
      }
      else {
        // Operator
        var tokPrec = OpPrecedence(token),
           headPrec = OpPrecedence(op_stack[op_stack.length - 1]);

        while ((OpAssociativity(token) === "L" && tokPrec <= headPrec) ||
          (OpAssociativity(token) === "R" && tokPrec < headPrec)) {

          rpn_expr.push([numArgs(op_stack[op_stack.length - 1]), op_stack.pop()]);
          if (op_stack.length === 0) break;

          headPrec = OpPrecedence(op_stack[op_stack.length - 1]);
        }

        op_stack.push(token);
      }
    }
  });

  // Push all remaining operators onto the final expression
  while (op_stack.length > 0) {
    var popped = op_stack.pop();
    if (popped === ")") {
      this.valid = false;
      break;
    }
    rpn_expr.push([numArgs(popped), popped]);
  }
}

/**
 * returns the result of evaluating the current expression
 */
Calc.prototype.eval = function(x) {
  var stack = [], rpn_expr = this.rpn_expr;

  rpn_expr.forEach(function(token) {
    if (typeof token[0] == "string") {
      switch (token[0]) {
        case "var":
          // Variable, i.e. x as in f(x); push value onto stack
          //if (token[1] != "x") return false;
          stack.push(x);
          break;

        case "num":
          // Number; push value onto stack
          stack.push(token[1]);
          break;
      }
    }
    else {
      // Operator
      var numArgs = token[0];
      var args = [];
      do {
        args.unshift(stack.pop());
      } while (args.length < numArgs);

      switch (token[1]) {
        /* BASIC ARITHMETIC OPERATORS */
        case "*":
          stack.push(args[0] * args[1]);
          break;
        case "/":
          stack.push(args[0] / args[1]);
          break;
        case "+":
          stack.push(args[0] + args[1]);
          break;
        case "-":
          stack.push(args[0] - args[1]);
          break;

        // exponents
        case "^":
          stack.push(Math.pow(args[0], args[1]));
          break;

        /* TRIG FUNCTIONS */
        case "sin":
          stack.push(Math.sin(args[0]));
          break;
        case "cos":
          stack.push(Math.cos(args[0]));
          break;
        case "tan":
          stack.push(Math.tan(args[0]));
          break;
        case "sec":
          stack.push(1 / Math.cos(args[0]));
          break;
        case "csc":
          stack.push(1 / Math.sin(args[0]));
          break;
        case "cot":
          stack.push(1 / Math.tan(args[0]));
          break;
        case "sinh":
          stack.push(.5 * (Math.pow(Math.E, args[0]) - Math.pow(Math.E, -args[0])));
          break;
        case "cosh":
          stack.push(.5 * (Math.pow(Math.E, args[0]) + Math.pow(Math.E, -args[0])));
          break;
        case "tanh":
          stack.push((Math.pow(Math.E, 2*args[0]) - 1) / (Math.pow(Math.E, 2*args[0]) + 1));
          break;
        case "sech":
          stack.push(2 / (Math.pow(Math.E, args[0]) + Math.pow(Math.E, -args[0])));
          break;
        case "csch":
          stack.push(2 / (Math.pow(Math.E, args[0]) - Math.pow(Math.E, -args[0])));
          break;
        case "coth":
          stack.push((Math.pow(Math.E, 2*args[0]) + 1) / (Math.pow(Math.E, 2*args[0]) - 1));
          break;


        case "floor":
          stack.push(Math.floor(args[0]));
          break;
        case "ceil":
          stack.push(Math.ceil(args[0]));
          break;

        default:
          // unknown operator; error out
          return false;
      }
    }
  });

  return stack.pop();
};

Calc.prototype.latexToInfix = function(latex) {
  /**
    * function: converts latex notation to infix notation (human-readable, to be converted
    * again to prefix in order to be processed
    *
    * Supported functions / operators / notation:
    * parentheses, exponents, adding, subtracting, multipling, dividing, fractions
    * trigonometric (including hyperbolic) functions, floor, ceil
    */

  var infix = latex;

  infix = infix
    .replace(/\\frac{([^}]+)}{([^}]+)}/g, "($1)/($2)") // fractions
    .replace(/\\left\(/g, "(") // open parenthesis
    .replace(/\\right\)/g, ")") // close parenthesis
    .replace(/[^\(](floor|ceil|(sin|cos|tan|sec|csc|cot)h?)\(([^\(\)]+)\)[^\)]/g, "($&)") // functions
    .replace(/([^(floor|ceil|(sin|cos|tan|sec|csc|cot)h?|\+|\-|\*|\/)])\(/g, "$1*(")
    .replace(/\)([\w])/g, ")*$1")
    .replace(/([0-9])([A-Za-z])/g, "$1*$2")
  ;

  return infix;
};

使用示例:

var latex = "e^x+\\frac{2}{3}x-4sin\\left(x\\right)";

var calc = new Calc(latex);

var test = calc.eval(3.5); // 36.85191820278412

答案 1 :(得分:3)

好吧,你将不得不在某个时候决定你支持哪些操作。在那之后,使用像Shunting-yard algorithm这样的解析器来实现评估器并不难以产生更容易评估的等式的表示(即抽象语法树)。

我有一个用JavaScript编写的这种评估器的简单示例:http://gjp.cc/projects/logic_tables.html它采用!(p ^^ q) & ~(p || q)之类的逻辑表达式而不是LaTeX,但它可能仍然是一个有用的示例。

JavaScript(http://gpittarelli.com/projects/logic_tables.js):

var CALCULATOR_CONSTANTS = {
    /* True values. */
    't': true,
    'true': true,

    /* False values. */
    'c': false,
    'false': false
};

// The Calculator constructor takes an expression and parses
// it into an AST (refered to as rpn_expr)
var Calculator = function(expr) {
    this.valid = true;
    var OpPrecedence = function(op) {
        return (op === "!" || op === "~")? 9

             : (op === "&" || op === "&&")? 7
             : (op === "|" || op === "||" )? 7
             : (op === "^" || op === "^^")? 7

             : (op === "->")? 5
             : (op === "<-")? 5

             : 0;
    }

    var OpAssociativity = function(op) {
        return (op === "!" || op === "~")? "R":"L";
    }

    this.rpn_expr = [];
    this.variables = [];
    var rpn_expr = this.rpn_expr;
    var variables = this.variables;

    expr = expr.replace(/\s+/g, "");

    // This nice long regex matches any valid token in a user
    // supplied expression (e.g. an operator, a constant or
    // a variable)
    var in_tokens = expr.match(/(\!|\~|\|+|&+|\(|\)|\^+|(->)|(<-)|[a-zA-Z0-9]+)/gi);
    var op_stack = [];

    in_tokens.forEach(function(token) {
        if (/[a-zA-Z0-9]+/.test(token)) {
            if (CALCULATOR_CONSTANTS.hasOwnProperty(token)) {
                // Constant.  Pushes a boolean value onto the stack.
                rpn_expr.push(CALCULATOR_CONSTANTS[token]);
            } else {
                // Variables
                rpn_expr.push(token);
                variables.push(token);
            }
        }
        else if (token === ")") {
            // Pop tokens off the op_stack onto the rpn_expr until we
            // reach the matching (
            while (op_stack[op_stack.length-1] !== "(") {
                rpn_expr.push(op_stack.pop());
                if (op_stack.length === 0) {
                    this.valid = false;
                    return;
                }
            }

            // Remove the (
            op_stack.pop();
        }
        else if (token === "(") {
            op_stack.push(token);
        }
        else {
            // Operator
            var tokPrec =  OpPrecedence( token ),
                headPrec = OpPrecedence( op_stack[op_stack.length-1] );
            while ((OpAssociativity(token) === "L" && tokPrec <= headPrec)
                || (OpAssociativity(token) === "R" && tokPrec <  headPrec) ) {
                rpn_expr.push(op_stack.pop());
                if (op_stack.length === 0)
                    break;
                headPrec = OpPrecedence( op_stack[op_stack.length-1] );
            }

            op_stack.push(token);
        }
    });

    // Push all remaining operators onto the final expression
    while (op_stack.length > 0) {
        var popped = op_stack.pop();
        if (popped === ")") {
            this.valid = false;
            break;
        }
        rpn_expr.push(popped);
    }

    this.optimize();
}

/** Returns the variables used in the currently loaded expression. */
Calculator.prototype.getVariables = function() { return this.variables; }

Calculator.prototype.optimize = function() {
    // Single-pass optimization, mainly just to show the concept.
    // Looks for statements that can be pre computed, eg:
    // p | true
    // q & false
    // r ^ r
    // etc...

    // We do this by reading through the RPN expression as if we were
    // evaluating it, except instead rebuild it as we go.

    var stack = [], rpn_expr = this.rpn_expr;

    rpn_expr.forEach(function(token) {
        if (typeof token === "boolean") {
            // Constant.
            stack.push(token);
        } else if (/[a-zA-Z0-9]+/.test(token)) {
            // Identifier - push onto the stack
            stack.push(token);
        } else {
            // Operator - The actual optimization takes place here.

            // TODO: Add optimizations for more operators.
            if (token === "^" || token === "^^") {
                var a = stack.pop(), b = stack.pop();

                if (a === b) { // p ^ p == false
                    stack.push(false);
                } else {
                    stack.push(b);
                    stack.push(a);
                    stack.push(token);
                }

            } else if (token === "|" || token === "||") {
                var a = stack.pop(), b = stack.pop();

                if (a === true || b === true) {
                    // If either of the operands is a tautology, OR is
                    // also a tautology.
                    stack.push(true);
                } else if (a === b) { // p | p == p
                    stack.push(a);
                } else {
                    stack.push(b);
                    stack.push(a);
                    stack.push(token);
                }
            } else if (token === "!" || token === "~") {
                var p = stack.pop();
                if (typeof p === "boolean") {
                    // NOT of a constant value can always
                    // be precalculated.
                    stack.push(!p);
                } else {
                    stack.push(p);
                    stack.push(token);
                }
            } else {
                stack.push(token);
            }
        }

    });

    this.rpn_expr = stack;
}

/**
 * returns the result of evaluating the current expressions
 * with the passed in <code>variables</code> object.  <i>variables</i>
 * should be an object who properties map from key => value
 */
Calculator.prototype.eval = function(variables) {
    var stack = [], rpn_expr = this.rpn_expr;

    rpn_expr.forEach(function(token) {
        if (typeof token === "boolean") {
            // Constant.
            stack.push(token);
        } else if (/[a-zA-Z0-9]+/.test(token)) {
            // Identifier - push its boolean value onto the stack
            stack.push(!!variables[token]);
        } else {
            // Operator
            var q = stack.pop(), p = stack.pop();
            if (token === "^" || token === "^^") {
                stack.push((p? 1:0) ^ (q? 1:0));
            } else if (token === "|" || token === "||") {
                stack.push(p || q);
            } else if (token === "&" || token === "&&") {
                stack.push(p && q);
            } else if (token === "!" || token === "~") {
                stack.push(p);
                stack.push(!q);
            } else if (token === "->") {
                stack.push((!p) || q);
            } else if (token === "<-") {
                stack.push((!q) || p);
            }
        }

    });

    return stack.pop()? 1:0;
};

答案 2 :(得分:3)

也许你可以试试LatexJS。 LatexJS是一个API服务,我把它放在一起,以便将乳胶数学符号转换为Javascript函数。因此,您将输入乳胶表达式并动态返回Javascript函数。例如:

<强>输入

x^2+3x-10sin\left(2x\right)

<强>输出

{
    "func": "(x)=>{return Math.pow(x,2)+3*x-10*Math.sin(2*x)};",
    "params": ["x"]
}

<强>评价

> func = (x)=>{return Math.pow(x,2)+3*x-10*Math.sin(2*x)};
> func(2)
< 17.56802495307928