我有一个包含一系列时间和活动的元组。所以,它将类似于:
('08:01: Woke Up\n08:05: Took Shower\n08:20: Ate Breakfast\n08:45: Left for work', )
我需要能够像以下一样单独进行每项活动和展示:
8:01 Woke Up
8:05 Took Shower
8:20 Ate Breakfast
8:45 Left for work
有人能给我一个关于在python中做到这一点的最佳/最简单方法的建议吗?谢谢。
答案 0 :(得分:9)
你已经在元素中有换行符,所以只需打印:
>>> tup = ('08:01: Woke Up\n08:05: Took Shower\n08:20: Ate Breakfast\n08:45: Left for work',)
>>> print tup[0]
08:01: Woke Up
08:05: Took Shower
08:20: Ate Breakfast
08:45: Left for work
您可以使用str.splitlines()
:
>>> tup[0].splitlines()
['08:01: Woke Up', '08:05: Took Shower', '08:20: Ate Breakfast', '08:45: Left for work']
>>> for line in tup[0].splitlines():
... print line
...
08:01: Woke Up
08:05: Took Shower
08:20: Ate Breakfast
08:45: Left for work
如果您需要将时间和活动作为单独的字符串,请拆分字符串': '
上的每一行:
>>> for line in tup[0].splitlines():
... time, activity = line.split(': ', 1)
... print time, activity
...
08:01 Woke Up
08:05 Took Shower
08:20 Ate Breakfast
08:45 Left for work
答案 1 :(得分:0)
>>> t = ('08:01: Woke Up\n08:05: Took Shower\n08:20: Ate Breakfast\n08:45: Left for work', )
>>> for elem in t:
... print elem.split('\n')
...
['08:01: Woke Up', '08:05: Took Shower', '08:20: Ate Breakfast', '08:45: Left fo
r work']
>>> for elem in t:
... for activity in elem.split('\n'):
... print activity
...
08:01: Woke Up
08:05: Took Shower
08:20: Ate Breakfast
08:45: Left for work
>>> for elem in t:
... print elem
...
08:01: Woke Up
08:05: Took Shower
08:20: Ate Breakfast
08:45: Left for work
答案 2 :(得分:0)
你似乎没有元组,你有一个字符串,如果你打印,会准确地给你你想要的。
假设你有一个元组列表(我认为这就是你的意思)你应该做这样的事情:
input = [("8:01", "Woke Up"), ("8:05", "Took shower"), ("8:20", "Ate Breakfast")]
for time, description in input:
print time, description
答案 3 :(得分:0)
dictionary = {}
dictionary['8:01'] = 'Woke Up'
dictionary['8:05'] = 'Took Shower'
dictionary['8:20'] = 'Ate Breakfast'
dictionary['8:45'] = 'Left for work'
然后以您可以简单的格式打印:
for k in dictionary:
print k + ' ' + dictionary[k]