Question

我的文件有一系列数字：9 1 2 1

我试图找出比率subsum / sum

#include <stdio.h>
void main()
{ 
    double subSum = 0;
    double sum    = 13;
    double num    = 0;
    double x      = 0;
    FILE*  file   = fopen("text.txt", "r");

    while (fscanf(file, "%f", &num) > 0)
    {
        subSum = subSum + num;
        x      = subSum / sum;

        printf("%f",x);
        printf("\n");
    }

    fclose(file);
}

但它会保持打印零（0.00000000000）为什么???

Answer 1

您将double变量的地址传递给scanf()格式，该格式已被告知期望float的地址。

while (fscanf(file, "%f", &num) > 0)

应该是：

while (fscanf(file, "%lf", &num) > 0)

Answer 2

#include<stdio.h>
void main()
{ 
double subSum=0;
double sum=13;
int num=0;
double x=0;
FILE *file = fopen("text.txt", "r");
while(fscanf(file, "%d", &num) > 0){
    subSum=subSum+(double)num;
    x= subSum / sum;
    printf("%f",x);
    printf("\n");
 }
fclose(file);
}

Answer 3

如果你的C编译器 NOT 支持“％lf”，那么：

 float  num;
 double dnum;

 // etc.

 scanf("%f", &num);

 //etc.

 dnum = (double) num;  // use dnum in calculations

从文件中读取并在C中打印双倍比率

3 个答案: