Question

我编写了以下程序，假设启动，显示表单并连接到服务器并获取消息。但是，当我开始它没有任何反应？

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using Lidgren.Network;
using System.Threading;

namespace WindowsGame2
{
    public partial class Form1 : Form
    {
        private NetClient client;
        private NetBuffer buffer;

        public Form1()
        {
            InitializeComponent();
        }

        private void Connect()
        {
            NetConfiguration config = new NetConfiguration("xesh");
            NetClient client = new NetClient(config);

            client.Connect("75.127.105.216", 14242);

            NetBuffer buffer = client.CreateBuffer();
        }

        private void ReceiveMessages()
        {
            Connect();
            bool keepGoing = true;
            while (keepGoing)
            {
                NetMessageType type;
                while (client.ReadMessage(buffer, out type))
                {
                    switch (type)
                    {
                        case NetMessageType.DebugMessage:
                            Console.WriteLine(buffer.ReadString());
                            break;

                        case NetMessageType.StatusChanged:
                            Console.WriteLine("New status: " + client.Status + " Reason: " + buffer.ReadString());
                            break;

                        case NetMessageType.Data:
                            break;
                    }
                }
            }
        }

        private void Update(string str)
        {
            ReceiveMessages();
            textBox1.AppendText(str + "\r\n");
        }

        private void textBox1_TextChanged(object sender, EventArgs e)
        {

        }

        static void Main(string[] args)
        {
            Form1 form = new Form1();
        }
    }
}

Answer 1

您已声明：

    private NetClient client;        
    private NetBuffer buffer;

然而，您的Connect（）方法构造新的本地客户端和缓冲区，当方法返回时，它将超出范围。实例的客户端和缓冲区永远不会被初始化，因此在ReceiveMessages（）方法中使用时没有任何意义。

Answer 2

你没有打电话给你的方法。

尝试：

static void Main(string[] args)
{
    Form1 form = new Form1();
    ReceiveMessages();
    // or 
    Update("Me");
}

表单上有任何按钮吗？有点需要更多信息

C＃聊天程序Lidgren

2 个答案: