Question

我对Android开发有点新手，在尝试创建一个名为areacircle的另一个活动的Intent时收到此错误：

Syntax error on token "(",; expected  
Syntax error on token ")",; expected   
void is an invalid type for the variable acircle

编辑：我添加了整个代码块

我希望此代码可以帮助您：

public class findmy extends Activity {
@Override
public void onCreate(Bundle savedInstanceState){
    super.onCreate(savedInstanceState);
    setContentView(R.layout.findmy);


    public void acircle(View view) {
        Intent acircleIntent = new Intent(this, areacircle.class);
        startActivity(acircleIntent);
                }
            }

}

Answer 1

更改

public void acircle(View view) {
Intent acircleIntent = new Intent(this, areacircle.class);
startActivity(acircleIntent);
        };
    }

要：

在;之后从第四行删除}，您的问题应该消失。

public void acircle(View view) {
Intent acircleIntent = new Intent(this, areacircle.class);
startActivity(acircleIntent);
        }
    }

Answer 2

如果您在点击按钮

上查看其他活动，请尝试这样做

public class findmy extends Activity {
 @Override
 public void onCreate(Bundle savedInstanceState){
    super.onCreate(savedInstanceState);
    setContentView(R.layout.findmy);
    Button d = (Button) findViewById(R.id.btnTitle3);
    d.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            Intent acircleIntent = new Intent(this, areacircle.class);
            startActivity(acircleIntent);
        }
    });

 }
}

令牌Android开发错误的语法错误

2 个答案: