在我的应用程序中,我将播放来自URL的音乐。所以还需要一些时间
播放音频,因为它是通过流媒体。
我想在等待MediaPlayer
播放/开始时实现ProgressDialog。
以下是播放音频的方法: public void playMedia(String songIndex){
ProgressDialog pDialog;
pDialog = new ProgressDialog(context);
pDialog.setMessage("Loading. . . ");
pDialog.setCancelable(false);
pDialog.show();
Uri songUri = Uri.parse(songIndex);
try {
mp.setDataSource(context, songUri);
mp.setAudioStreamType(AudioManager.STREAM_MUSIC);
mp.prepare();
} catch (IllegalArgumentException e) {
e.printStackTrace();
} catch (IllegalStateException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}finally{
pDialog.dismiss();
}
if(mp!=null)
mp.start();
}
这就是我尝试实现它的方式。 但它没有用。 我有这样的例外:
08-27 19:48:13.896: E/InputEventReceiver(8798): Exception dispatching input event.
08-27 19:48:13.896: E/MessageQueue-JNI(8798): Exception in MessageQueue callback: handleReceiveCallback
08-27 19:48:13.906: E/MessageQueue-JNI(8798): android.view.WindowManager$BadTokenException: Unable to add window -- token null is not for an application
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at android.view.ViewRootImpl.setView(ViewRootImpl.java:599)
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:326)
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:224)
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at android.view.WindowManagerImpl$CompatModeWrapper.addView(WindowManagerImpl.java:149)
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at android.app.Dialog.show(Dialog.java:285)
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at com.app.adapters.MyRowAdapter.playMedia(MyRowAdapter.java:126)
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at com.app.adapters.MyRowAdapter$2$4.onTouch(MyRowAdapter.java:522)
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at android.view.View.dispatchTouchEvent(View.java:7185)
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at android.view.ViewGroup.dispatchTransformedTouchEvent(ViewGroup.java:2280)
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:2023)
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at android.view.ViewGroup.dispatchTransformedTouchEvent(ViewGroup.java:2280)
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:2023)
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at android.view.ViewGroup.dispatchTransformedTouchEvent(ViewGroup.java:2280)
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:2023)
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at android.view.ViewGroup.dispatchTransformedTouchEvent(ViewGroup.java:2280)
08-27 19:48:13.906: E/MessageQueue-JNI(8798): at android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:2023)
还有其他方法可以实现吗?我应该把这个放在哪里? 提前谢谢。
答案 0 :(得分:0)
如果你引用了getApplicationContext(),那么你在这里使用的上下文对象pDialog = new ProgressDialog(context);
将不起作用。
而是尝试将其替换为,像这样的活动上下文,
pDialog = new ProgressDialog(ActivityName.this);
答案 1 :(得分:0)
Use Async Task:
private class MediaPlayer extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... params) {
Uri songUri = Uri.parse(songIndex);
try {
mp.setDataSource(context, songUri);
mp.setAudioStreamType(AudioManager.STREAM_MUSIC);
mp.prepare();
} catch (IllegalArgumentException e) {
e.printStackTrace();
} catch (IllegalStateException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return mp;
}
@Override
protected void onPostExecute(String result) {
}
@Override
protected void onPreExecute() {
ProgressDialog pDialog;
pDialog = new ProgressDialog(context);
pDialog.setMessage("Uploading file. . . ");
pDialog.setCancelable(false);
pDialog.show();
}
@Override
protected void onProgressUpdate(Void... values) {
}
}