Question

我有一个由常规文本输入和文件上传组成的表单。

<portlet:actionURL var='create' name="addProduct">
</portlet:actionURL>    
<form id="addform" action="<%=create%>" method="post" enctype="multipart/form-data">

    <dl class="dl-horizontal">
        <dt>Product Name</dt>
        <dd>
            <input type="text"  name="name"  />
        </dd>
        <dt>Image File</dt>
        <dd>
            <input type="file" name="imgFile" >
        </dd>
    </dl>
        <button type="submit">Save</button>
</form>

在portlet类中我想访问上传的文件和参数“name”。我发现当我在我的表单中放入enctype =“multipart / form-data”时，我无法得到其他（这里是“name”参数） request.getParameter（“name”）或 ParamUtil.getString（request，“name”）。

但是当我删除enctype =“multipart / form-data”时，我可以看到“name”参数，但当然错过了上传的文件。我怎样才能同时上传文件和常规参数

编辑：我的行动实施是：

@ProcessAction(name = "addProduct")
public void addProduct(ActionRequest request, ActionResponse response) {
        String name = ParamUtil.getString(request,"name");
            String anotherTryForName = request.getParameter("name");
        System.out.println(name);
            System.out.println(anotherTryForName);
        System.out.println(uploadImg(request));
}
private String uploadImg(ActionRequest request) {

        String realPath = getPortletContext().getRealPath("/");
        byte[] bytes = null;
        try {

            UploadPortletRequest uploadRequest = PortalUtil
                    .getUploadPortletRequest(request);
            String sourceFileName = uploadRequest.getFileName("imgFile");
            File file = uploadRequest.getFile("imgFile");
            try {
                bytes = FileUtil.getBytes(file);
            } catch (IOException e2) {
                e2.printStackTrace();
            }
            File newFile = null;

            if ((bytes != null) && (bytes.length > 0)) {

                try {
                    newFile = new File(realPath + "demo/productimg/"
                            + sourceFileName);
                    FileInputStream fileInputStream = new FileInputStream(file);
                    FileOutputStream fileOutputStream = new FileOutputStream(
                            newFile);
                    fileInputStream.read(bytes);
                    fileOutputStream.write(bytes, 0, bytes.length);
                    fileOutputStream.close();
                    fileInputStream.close();
                } catch (FileNotFoundException e) {
                    System.out.println("File Not Found.");
                    e.printStackTrace();
                } catch (IOException e1) {
                    System.out.println("Error Reading The File.");
                    e1.printStackTrace();
                }
            }
            return sourceFileName;
        } catch (Exception e) {
            System.out.println("Exception::::" + e.getMessage());
            return "";
        }
}

Answer 1

发现当表单是multipart / form-data时，我应该从UploadPortletRequest而不是ActionRequest获得额外的参数（比如“name”）。

获取参数的正确形式：

UploadPortletRequest uploadRequest = PortalUtil
                    .getUploadPortletRequest(request);
String name = ParamUtil.getString(uploadRequest,"name");

Answer 2

当您发布到portlet操作时，参数应该命名为portlet。尝试

 <input type="text" name="<portlet:namespace/>name"/>
 ...
 <input type="file" name="<portlet:namespace/>imgFile"/>

或者你可以使用aui taglib，例如

 <aui:form ...>
    <aui:input ... name="name"/>
 </aui:form>

此taglib会自动添加命名空间

如何在liferay操作中访问multipart / form-data表单参数

2 个答案: