Question

我的字符串：

download_recording true Package available http://abc.com/recDownload/635131586215948750.exe

如何从上面的字符串中获取http://abc.com/recDownload/635131586215948750.exe？

请帮助

Answer 1

此博客包含示例代码：

http://blog.houen.net/java-get-url-from-string/

以及这个问题：

Detect and extract url from a string?

这也可能有所帮助：

How to detect the presence of URL in a string

Answer 2

这是一个非常简单的匹配包含前缀协议的东西。 [a-z]+:\/\/[^ \n]*

Pattern.compile("[a-z]+:\/\/[^ \n]*").matcher(
    "download_recording true Package available http://abc.com/recDownload/635131586215948750.exe click the link"
).find();
//"http://abc.com/recDownload/635131586215948750.exe"

等效的javascript

'download_recording true Package available http://abc.com/recDownload/635131586215948750.exe click the link'
    .match(/[a-z]+:\/\/[^ \n]*/)

Answer 3

从字符串类中简单使用split方法就可以解析它。

String s = "download_recording true Package available http://abc.com/recDownload/635131586215948750.exe";
//We now have the values on either side of where http:// was
String[] splitted = s.split("http://");
//so index 1 is the url and we can just append http:// back on the beginning to get the whole url
String url = "http://" + splitted[1];

Answer 4

我认为这个正则表达式是您正在寻找的：

(http\:\/\/){0,1}(www){0,1}[\.]{0,1}[a-zA-Z0-9_]+\.[a-zA-Z0-9_]+(\/{1}[a-zA-Z0-9_\.]+)*

如何在java中使用正则表达式模式从字符串中提取链接？

4 个答案: