Question

我尝试通过Graphstream在java中构建图形。我希望有两种类型的节点，默认情况下形状为圆形或方框。因此将类分配给节点。代码：

 System.setProperty("org.graphstream.ui.renderer","org.graphstream.ui.j2dviewer.J2DGraphRenderer");
 Graph g1= new  MultiGraph("db");
 g1.addAttribute("ui.stylesheet", "ui.label"," node.att{shape:box;}");
 Node n1 = g1.addNode("a");
 n1.setAttribute("ui.class","att");
 g1.display();

但是在显示中节点不是框，并且在输出中是圆圈并带有此消息：

“样式表规范错误如何处理'[Ljava.lang.Object; @ 192b996'？”

我哪里错了？谢谢你的帮助。

Answer 1

import javax.swing.JFrame;
import javax.swing.JPanel;

import org.graphstream.graph.*;
import org.graphstream.graph.implementations.*;
import org.graphstream.ui.spriteManager.Sprite;
import org.graphstream.ui.spriteManager.SpriteManager;
import org.graphstream.ui.swingViewer.View;
import org.graphstream.ui.swingViewer.Viewer;

public class Main {
    /**
     * @param args
     */
    public static void main(String[] args) {
        Graph graph = new MultiGraph("graph");

        String styleSheet="node {"+
   " fill-color: grey;"+
   " size: 10px;"+
   " stroke-mode: plain;"+
   " stroke-color: black;"+
   " stroke-width: 1px;"+
   "}"+
   "node.important {"+
   " fill-color: red;"+
   " size: 30px;"+
   "}";

        graph.addNode("A");
        graph.addNode("B");
        graph.addEdge("AB", "A", "B");
        Node e1=graph.getNode("A");
        graph.addAttribute("ui.stylesheet", styleSheet);

        e1.addAttribute("ui.class", "important"); 
        e1.addAttribute("ui.label", "A Node");
        //e1.addAttribute( "ui.hide" );

        graph.display();
    }

}

如何将类分配给graphstream中的节点

1 个答案: