ruby-on-rails-3 - 如何使用MongoDB查询和索引更快地获得结果

我正在运行Rails应用程序并使用mongoid。我在我的rails应用程序中创建了帐户Mongoid::Document 帐户文档中有大量记录，我添加了复合索引来加快查询速度。但申请表现不佳我尝试对查询进行解释，但indexOnly属性显示为false值。

任何人都可以让我知道创建复合指数的最佳方法是什么如何检查我写的查询是否正确使用索引？

这是我的查询

first_record = Account.where(column_1: 5, column_2: "xxxx", column_3: "xxxxxx", column_4: "xxxxxxxxxxx", column_5: "xxxxxxxxx")

first_record.explain() => {"cursor"=>"BtreeCursor provider_5_params_idx", "isMultiKey"=>false, "n"=>10320, "nscannedObjects"=>10320, "nscanned"=>10320, "nscannedObjectsAllPlans"=>10320, "nscannedAllPlans"=>10320, "scanAndOrder"=>false, "indexOnly"=>false, "nYields"=>317, "nChunkSkips"=>0, "millis"=>222464, "indexBounds"=>{"column_1"=>[[5, 5]], "column_2"=>[["xxxx", "xxxx"]], "column_3"=>[["xxxxx", "xxxxx"]], "column_4"=>[["pxxxx", "xxxxxxx"]], "column_5"=>[["xxxxxx", "xxxxxx"]]}, "allPlans"=>[{"cursor"=>"BtreeCursor provider_5_params_idx", "n"=>10320, "nscannedObjects"=>10320, "nscanned"=>10320, "indexBounds"=>{"column_1"=>[[5, 5]], "column_2"=>[["xxxx", "xxxx"]], "column_3"=>[["xxxx", "xxxx"]], "column_4"=>[["xxxx", "xxxxx"]], "column_5"=>[["xxxxx", "xxxxx"]]}}], "oldPlan"=>{"cursor"=>"BtreeCursor provider_5_params_idx", "indexBounds"=>{"column_1"=>[[5, 5]], "column_2"=>[["xxxx", "xxxx"]], "column_3"=>[["xxxxx", "xxxxx"]], "column_4"=>[["xxxx", "xxxxx"]], "column_5"=>[["xxxxx", "xxxxx"]]}}, "server"=>"xxxxxxxxx"}

我也用以下方式创建了索引 db.account.ensureIndex({column_1:1,column_2:1,column_3:1,column_4:1,column_5:1}, {name:"provider_5_params_idx",background:true});

如何使用MongoDB查询和索引更快地获得结果

1 个答案: