Question

我遇到了分离如何处理两个JSOn响应的问题。如果只返回一个元素，它会给出不同于两个的响应：

这是一个结果：

{
    "voteMap": {
        "SID": "2727",
        "CNT": "1",
        "VTD": "N"
    }
}

还有两个：

{
    "voteMap": [
        {
            "SID": "2814",
            "CNT": "1",
            "VTD": "N"
        },
        {
            "SID": "2815",
            "CNT": "1",
            "VTD": "N"
        }
    ]
}

我从拥有一个数组到拥有一系列字典。以下是我处理它的方式：

responseArr = jsonArray[@"voteMap"];

  if([jsonArray count] == 1){
       Song* song = [self findSong:[responseArr valueForKey:@"SID"]];
       song.votes =[responseArr valueForKey:@"CNT"];
       song.status = [responseArr valueForKey:@"VTD"];
        }           
   else{
         for (NSDictionary *dict in responseArr) {
            Song *song = [self findSong:[dict valueForKey:@"SID"]];
            song.votes =[dict valueForKey:@"CNT"];
            song.status = [dict valueForKey:@"VTD"];
            }
        }

抱歉格式不正确。发生的事情是[jsonArray count] == 1总是在发生......因为它总是返回voteMap

Answer 1

我建议用这样的方式检查类型：

id object = [response objectForKey:@"voteMap"];
if ([object isKindOfClass:[NSArray class]]) {
    // process multible objects
} else if ([object isKindOfClass:[NSDictionary class]]) {
    // process individual object
}

Answer 2

responseArr = jsonArray[@"voteMap"];
    if ([responseArr isKindOfClass:[NSArray class]]) {
        for (NSDictionary *dict in responseArr) {
            Song *song = [self findSong:[dict valueForKey:@"SID"]];
            song.votes =[dict valueForKey:@"CNT"];
            song.status = [dict valueForKey:@"VTD"];
            }
    }
    if ([responseArr isKindOfClass:[NSDictionary class]]) {
Song* song = [self findSong:[responseArr valueForKey:@"SID"]];
       song.votes =[responseArr valueForKey:@"CNT"];
       song.status = [responseArr valueForKey:@"VTD"];
        }  

    }

我认为这会对你有所帮助。

Answer 3

您可以使用isKindOfClass方法确定它是NSArray或NSDictionary。

Answer 4

尝试以下代码。并检查json是数组还是字典

id jsonArray;
if([jsonArray isKindOfClass:[NSArray class]]){

    Song* song = [self findSong:[responseArr valueForKey:@"SID"]];
    song.votes =[responseArr valueForKey:@"CNT"];
    song.status = [responseArr valueForKey:@"VTD"];
}
else{
    for (NSDictionary *dict in responseArr) {
        Song *song = [self findSong:[dict valueForKey:@"SID"]];
        song.votes =[dict valueForKey:@"CNT"];
        song.status = [dict valueForKey:@"VTD"];
    }
}

Answer 5

NSArray* responseArr = [response objectForKey:@"voteMap"];
if ([responseArr isKindOfClass:[NSDictionary class]]) {
   responseArr = [NSArray arrayWithObject:responseArr];
}
for (NSDictionary *dict in responseArr) {
    Song *song = [self findSong:[dict valueForKey:@"SID"]];
    song.votes =[dict valueForKey:@"CNT"];
    song.status = [dict valueForKey:@"VTD"];
}

（我已多次使用过这个模型。）

区分两个JSON响应

5 个答案: