我正在关注教程,当我点击提交按钮时没有任何反应。我添加了一个警报,看看该函数是否运行。它运行警报。
[代码]
<!-- THE HTML PAGE AND JAVASCRIPT -->
<html>
<head>
<script language="JavaScript" type="text/javascript">
function ajax_post(){
// added by me to test
alert("Hello");
// Create our XMLHttpRequest object
var hr = new XMLHttpRequest();
// Create some variables we need to send to our PHP file
var url = "my_parse_file.php";
var fn = document.getElementById("first_name").value;
var ln = document.getElementById("last_name").value;
var vars = "firstname="+fn+"&lastname="+ln;
hr.open("POST", url, true);
// Set content type header information for sending url encoded variables in the request
hr.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
// Access the onreadystatechange event for the XMLHttpRequest object
hr.onreadystatechange = function() {
if(hr.readyState == 4 && hr.status == 200) {
var return_data = hr.responseText;
document.getElementById("status").innerHTML = return_data;
}
}
// Send the data to PHP now... and wait for response to update the status div
hr.send(vars); // Actually execute the request
document.getElementById("status").innerHTML = "processing...";
}
</script>
</head>
<body>
<h2>Ajax Post to PHP and Get Return Data</h2>
Your First Name: <input id="first_name" name="first_name" type="text" />
<br /><br />
Your Last Name: <input id="last_name" name="last_name" type="text" />
<br /><br />
<input name="myBtn" type="submit" value="Submit Data" onClick="javascript:ajax_post();">
<br /><br />
<div id="status"></div>
</body>
</html>
[PHP]
<?php
echo 'Thank you '. $_POST['firstname'] . ' ' . $_POST['lastname'] . ', says the PHP file';
?>
我在这里做错了什么? 它根本不会给出任何错误。请帮帮我。
答案 0 :(得分:0)
试试这个
HTML
<h2>Ajax Post to PHP and Get Return Data</h2>
<form id="form">
Your First Name: <input id="first_name" name="first_name" type="text" />
<br /><br />
Your Last Name: <input id="last_name" name="last_name" type="text" />
<br /><br />
<input name="myBtn" type="submit" value="Submit Data">
<br /><br />
</form>
<div class="status"></div>
的javascript
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
$(function(){
$("#form") .submit(function(){
var first_name = $("#first_name") .val();
var last_name = $("#last_name") .val();
var s = {
"first_name":first_name,
"last_name":last_name
}
$.ajax({
url:'action.php',
type:'post',
data:s,
beforeSend: function (){
$(".status") .html("<img src=\"style/img/ajax/load1.gif\" alt=\"Loading ....\" />");
},
success:function(data){
$(".status").html(data);
}
});
});
})
</script>