Question

如果我为具有嵌套类的类重载运算符new和delete：

class A
{
public:
    static void* operator new(size_t);
    static void operator delete(void*);

    class B;
}

A::B对象中A::B个对象和分配实例的分配是否会使用重载的A::new和A::delete或全局默认值？

Answer 1

首先，您不需要重载new或delete，并且应该避免这样做，这可能性非常高。

Baring that，重载的运算符将应用于类A，而不是类A::B。如果您希望B具有重载运算符，则还需要在类B中重载它们。

有关如何重载new和delete的示例：http://www.cprogramming.com/tutorial/operator_new.html

Answer 2

没有

class A
{
public:
    A(){printf("A\n");}
    ~A(){}
    static void* operator new(size_t t){
        printf("A new\n");
        ::operator new(t);
    }
    static void operator delete(void* t){
        printf("A delete\n");
        ::operator delete(t);
    }

    void check_B(){
        b = new B();
        ::operator delete(b);
    }

    class B{
    public:
        B(){}
    };

    B* b;
};

class C : public A {

};

试验：

int main(void)
{
    A* a = new A;
    printf("\ncheck ------\n");
    a->check_B();
    printf("\ncheck ------\n");
    delete a;

    C* c = new C;
    A* cc = new C;

    delete c;
    delete cc;
return 0;
}

输出：

A

新A

检查------

检查------

删除

新的

A

新的

A

删除

删除

RUN SUCCESSFUL（总时间：64ms）

的valgrind：

==9318== 
==9318== HEAP SUMMARY:
==9318==     in use at exit: 0 bytes in 0 blocks
==9318==   total heap usage: 4 allocs, 4 frees, 25 bytes allocated
==9318== 
==9318== All heap blocks were freed -- no leaks are possible
==9318== 
==9318== For counts of detected and suppressed errors, rerun with: -v
==9318== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 2 from 2)

除非您重载new A[]，否则甚至不会调用operator new[]()。您需要相应地为嵌套类A::B重载它们。但是，正如我们所看到的，它们将被调用派生自A的类。

测试，测试，测试。测试总是优于不测试。作者：我。

关于嵌套类的operator new的重载决策

2 个答案: