Question

所以我必须解析包含嵌套标签的丑陋文件，例如

<p>blah<strong>lah</strong>blah</p>

嵌套标签已定义，我不关心它们。但它们使XmlPullParser失败：

XmlPullParser parser = XmlPullParserFactory.newInstance().newPullParser();
parser.setInput(some_reader);
while (parser.next() != XmlPullParser.END_DOCUMENT) {
    if (XmlPullParser.START_TAG == event) {
        String tag = parser.getName();
        if (tag != null) {
            tag = tag.toLowerCase();
        } else {
            continue;
        }
       if ("p".equals(tag)) {
           String text = parser.nextText();
           // and here we go
           // org.xmlpull.v1.XmlPullParserException: expected: /p read: strong
        }
    }
}

问题：我有可能在没有预处理文件的情况下剥离所有不必要的标签或使用第三方库吗？

编辑：更新了片段以确实有意义。

Answer 1

所以我摆脱了XMLPullParser并切换到SAXParser。此外，it performs better。

Answer 2

package com.xml;
import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;
import android.util.Log;

public class FeedHandler extends DefaultHandler {

    StringBuilder sb = null;
    String ret = "";
    boolean bStore = false;
    int howMany = 0;

    FeedHandler() {   }

    String getResults()
    {
        return "XML parsed data.\nThere are [" + howMany + "] status updates\n\n" + ret;
    }
    @Override
    public void startDocument() throws SAXException 
    {
        // initialize "list"
    }

    @Override
    public void endDocument() throws SAXException
    {

    }

    @Override
    public void startElement(String namespaceURI, String localName, String qName, Attributes atts) throws SAXException {

        try {
            if (localName.equals("status"))
            {
                this.sb = new StringBuilder("");
                bStore = true;
            }
            if (localName.equals("user")) 
            {
                bStore = false;
            }
            if (localName.equals("text")) 
            {
                this.sb = new StringBuilder("");
            }
            if (localName.equals("created_at")) 
            {
                this.sb = new StringBuilder("");
            }
        } catch (Exception e) 
        {

            Log.d("error in startElement", e.getStackTrace().toString());
        }
    }
    @Override

    public void endElement(String namespaceURI, String localName, String qName) throws SAXException 
    {

        if (bStore) 
        {
            if (localName.equals("created_at"))
            {
                ret += "Date: " + sb.toString() + "\n"; 
                sb = new StringBuilder("");
                return;

            }

            if (localName.equals("user"))
            {
                bStore = true;
            }

            if (localName.equals("text")) 
            {

                ret += "Post: " + sb.toString() + "\n\n";
                sb = new StringBuilder("");
                return;

            }


        }
        if (localName.equals("status"))
        {
            howMany++;
            bStore = false;
        }
    }
    @Override

    public void characters(char ch[], int start, int length)
    {

        if (bStore) 
        {
            String theString = new String(ch, start, length);

            this.sb.append(theString);
        }
    }

}

这是我的扩展Activity

的xmlActivity类

            InputSource is = new InputSource(getResources().openRawResource(R.raw.my));
            System.out.println("running xml file..... ");
        // create the factory
        SAXParserFactory factory = SAXParserFactory.newInstance();

        // create a parser
        SAXParser parser = factory.newSAXParser();

        // create the reader (scanner)
        XMLReader xmlreader = parser.getXMLReader();

        // instantiate our handler
        FeedHandler fh = new FeedHandler();

        // assign our handler
        xmlreader.setContentHandler(fh);

        // perform the synchronous parse
        xmlreader.parse(is);

        // should be done... let's display our results
        tvData.setText(fh.getResults());

使用xmlpullparser解析类似html的文档？

2 个答案: