在Chrome中使用JavaScript读取XML文件

时间:2013-08-26 10:39:10

标签: javascript xml xmldom

我需要使用JavaScript加载和读取XML文件。

以下代码在Firefox,IE和Opera中运行良好:

function loadXMLDoc(dname) {
  var xmlDoc

  // Internet Explorer
  try {
    xmlDoc = new ActiveXObject('Microsoft.XMLDOM')
  }
  catch (e) {
    // Firefox, Opera, etc.
    try {
      xmlDoc = document.implementation.createDocument('', '', null)
    }
    catch (e) {
      alert(e.message)
    }
  }

  try {
    xmlDoc.async = false
    xmlDoc.load(dname)
    return xmlDoc
  }
  catch (e) {
    alert(e.message)
  }

  return null
}

但是在Chrome中执行此代码会给我这个错误:

  

对象#没有方法“加载”

4 个答案:

答案 0 :(得分:5)

旧版代码

document.implementation.createDocument无法在Chrome和Safari上使用。

尽可能使用XMLHttpRequest

function loadXMLSync(url) {
  try {
    // Prefer XMLHttpRequest when available
    var xhr = new XMLHttpRequest()
    xhr.open('GET', url, false)
    xhr.setRequestHeader('Content-Type', 'text/xml')
    xhr.send()

    return xmlhttp.responseXML
  }
  catch (e) {
    // XMLHttpRequest not available, fallback on ActiveXObject
    try {
      var activex = new ActiveXObject('Microsoft.XMLDOM')
      activex.async = false
      activex.load(url)

      return activex
    }
    catch (e) {
      // Neither XMLHttpRequest or ActiveXObject are available
      return undefined
    }
  }
}

现代浏览器

如果您的目标是现代浏览器(> IE6),请使用XMLHttpRequest:

function loadXMLSync(url) {
  var xhr = new XMLHttpRequest()

  xhr.open('GET', url, false)
  xhr.setRequestHeader('Content-Type', 'text/xml')
  xhr.send()

  return xhr.responseXML
}

答案 1 :(得分:1)

在MDN上,有指导使用XMLHttpRequest。但是,在深入了解返回类型并且看到Google Chrome不支持XMLDocument之前,从DOMImplementation.createDocument开始并不清楚。 example on W3Schools使用XMLHttpRequest。

答案 2 :(得分:0)

按照这个来打印,加载,追加xml数据。这里的xml作为字符串存储在javascript中。这个方法适用于chrome,firefox希望它也适用于其他人

txt="<papers>"+"<paper>"+
 "<author>athor name</author>"+
"<title>title</title>"+
"<path>path</path>"+
"<track>which tack</track>"+
 "</paper>"+
"<paper>"+
"<author>athor name</author>"+
"<title>title</title>"+
"<path>path</path>"+
"<track>which tack</track>"+
"</paper>"+
"<paper>"+
"<author>athor name</author>"+
"<title>title</title>"+
"<path>path</path>"+
"<track>which tack</track>"+
"</paper>"+
"<papers>";
if (window.DOMParser)
  {
      parser=new DOMParser();
  xmlDoc=parser.parseFromString(txt,"text/xml");

   }
   else // Internet Explorer
    {
     xmlDoc=new ActiveXObject("Microsoft.XMLDOM");
     xmlDoc.async=false;
     xmlDoc.loadXML(txt);
    }

x=xmlDoc.getElementsByTagName("paper"); 
for (var i = 0; i < x.length; i++) {  
    var athor =x[i].childNodes[0].firstChild.nodeValue;
    var title = x[i].childNodes[1].firstChild.nodeValue;
    var path = x[i].childNodes[2].firstChild.nodeValue;
    var tack =x[i].childNodes[3].firstChild.nodeValue;
    //do something with these values...
    //each iteration gives one paper details    
    var xml=document.getElementById("element_id");//<div id="element_id"></div>
    var li = document.createElement("br");// create a new <br>  
    newlink = document.createElement('A'); // creating an <a> element
    newlink.innerHTML = athor;// adding <a>athor value here</a>
    newlink.setAttribute('href', path);// <a href="path"></a>

    newlink.appendChild(li);// <a href="path">athor</a><br>
    document.getElementById("element_id").appendChild(newlink);
//finaly it becomes <div id="element_id"><a href="path">athor</a><br></div>


}

我发布了这个答案here

答案 3 :(得分:0)

添加

    var xhr = new XMLHttpRequest(); 
    xhr.open("GET", "/example/xdom/books.xml", false); 
    xhr.send(null); 
    xmlDoc = xhr.responseXML.documentElement; 
    return xmlDoc;

catch语句中。如下所示:

function loadXMLDoc(dname) {
  var xmlDoc

  // Internet Explorer
  try {
    xmlDoc = new ActiveXObject('Microsoft.XMLDOM')
  }
  catch (e) {
    // Firefox, Opera, etc.
    try {
      xmlDoc = document.implementation.createDocument('', '', null)
    }
    catch (e) {
      alert(e.message)
    }
  }

  try {
    xmlDoc.async = false
    xmlDoc.load(dname)
    return xmlDoc
  }
  catch (e) {
    //alert(e.message)
    // For Chrome 
    var xhr = new XMLHttpRequest(); 
    xhr.open("GET", "/example/xdom/books.xml", false); 
    xhr.send(null); 
    xmlDoc = xhr.responseXML.documentElement; 
    return xmlDoc;
  }

  return null
}