Question

我有很多功能可以提供当年的周数，一年中的一周给出一年中当年的年数减去当前一周的年份差异，并将它们的差值模数减去两个。

我想创建单个方法，它接受两个输入，当前年份（“2013”）和当前日期“26/08/2013”并返回他们的差值模2为0或1。

int totalWeeks = getTotalWeeksInYear(2013);
int currentWeeks = getcurrentweekofYear("26/08/2013");

private int getTotalWeeksInYear(int year) {
    Calendar cal = Calendar.getInstance();
    cal.set(Calendar.YEAR, year);
    cal.set(Calendar.MONTH, Calendar.DECEMBER);
    cal.set(Calendar.DAY_OF_MONTH, 31);

    int ordinalDay = cal.get(Calendar.DAY_OF_YEAR);
    int weekDay = cal.get(Calendar.DAY_OF_WEEK) - 1; // Sunday = 0
    int numberOfWeeks = (ordinalDay - weekDay + 10) / 7;
    System.out.println(numberOfWeeks);
    return numberOfWeeks ;

}

private int getcurrentweekofYear(String week) {
    // String dtStart = "26/10/2013"; // Input date from user
    String dtStart = week; 
    SimpleDateFormat format = new SimpleDateFormat("dd/M/yyyy");  
    try {  
        date = format.parse(dtStart);
    } catch (ParseException e) {  
        // TODO Auto-generated catch block  
        e.printStackTrace();  
    }
    Calendar calender = new GregorianCalendar();
    calender.setTime(date);

    return calender.get(Calendar.WEEK_OF_YEAR) ;
}

int diffrence = totalWeeks - currentWeeks;
int remainder = diffrence % 2; 
if (remainder == 0)
{
    Toast.makeText(this, "current year weeks is 0", 
    Toast.LENGTH_SHORT).show();     
}
else
{
    if (remainder == 1)
    {
        Toast.makeText(this, "current year weeks is 1" , 
                       Toast.LENGTH_SHORT).show();  
    }
}

Answer 1

您可以在getTotalWeeksInYear（）的第一个函数中使用Calendar.WEEK_OF_YEAR;

int xyz(String date){
    // get week of year for the above date, you will get currentWeeks
    // Split String at '/' and get the year
    // Create new calendar with the for December 31 and year from above splitting
    // again get week of year , you will get totalWeeks 
    int diffrence= totalWeeks -currentWeeks;
    int remainder = diffrence % 2;
    Toast.makeText(this, "current year weeks is "+remainder , 
    Toast.LENGTH_SHORT).show();
    return remainder ;
 }

Answer 2

int result(int year, String week) {

SimpleDateFormat format = new SimpleDateFormat("dd/M/yyyy"); 

Calendar cal1 = Calendar.getInstance();
cal1.set(Calendar.YEAR, year);
cal1.set(Calendar.MONTH, Calendar.DECEMBER);
cal1.set(Calendar.DAY_OF_MONTH, 31);

try {  
    Date date = format.parse(week);
} catch (ParseException e) {   
    e.printStackTrace();  
}

Calendar cal2 = new GregorianCalendar();
calender.setTime(date);

return ((( cal.get(Calendar.DAY_OF_YEAR) - (cal.get(Calendar.DAY_OF_WEEK) - 1) + 10) / 7) - cal2.get(Calendar.WEEK_OF_YEAR) %2) ;

}

虽然我不知道，但是没有任何逻辑，所以为什么你不能写它。

将各种日期计算折叠到一个函数中

2 个答案: