茉莉花 - 同样方法的两个间谍

Question

我是Jasmine的新手，我想知道我们是否可以为同一方法创建2个间谍。这是我正在尝试的。

describe('something', function () {
    beforeEach(function () {
        mySpy = jasmine.createSpyObj('mySpy', 'functionInInterest');
        mySpy.functionInInterest.andCallFake(function (cb) {cb(something);});
    }

    //Some Test Cases
    describe('Here is the action!', function () {
        mySpy = jasmine.createSpyObj('mySpy', 'functionInInterest');
        mySpy.functionInInterest.andCallFake(function (cb) {cb(somethingElse);});
        //Some test cases that depends on somethingElse
    });
});

Here is the action!之前的测试用例取决于mySpy.functionInInterest.andCallFake(function (cb) {cb(something);}); Here is the action!中的测试用例取决于mySpy.functionInInterest.andCallFake(function (cb) {cb(somethingElse);});

注意：两者名称相同

我怎样才能做到这一点？提前谢谢！

Answer 1

而不是

describe('Here is the action!', function () {
        mySpy = jasmine.createSpyObj('mySpy', 'functionInInterest');
        mySpy.functionInInterest.andCallFake(function (cb) {cb(somethingElse);});
        //Some test cases that depends on somethingElse
    });

这样做

describe('Here is the action!', function () {
        mySpy_2 = jasmine.createSpyObj('mySpy', 'functionInInterest');
        mySpy_2.functionInInterest.andCallFake(function (cb) {cb(somethingElse);});
        //Some test cases that depends on somethingElse
    });