Question

我的A是640x1单元格，其中每个单元格A(i,1)的值因行而异，例如：

A(1,1)=[]
A(2,1)=[1]
A(3,1)=[1,2,3]

我想要做的是将A转换为：

A(1,1)=[]
A(2,1)=1
A(3,1)=1; A(3,2)=2; A(3,3)=3

以便每个单元格只有一个值。所以，如果有人可以帮助我，我该怎么办呢？这是A看起来像

的一部分

A=
[]
0
0
0
145
[144;192]
[145;197;307]

Answer 1

示例：

% first lets create some random cellarray containing data of different length
A = cell(10,1);
for i=1:numel(A)
    A{i} = rand(1,randi([0 5]));
end

% determine the maximum number of columns
colnum = max(cellfun(@numel, A));

% create new cellarray, and fill each row
B = cell(numel(A),colnum);
for i=1:numel(A)
    if isempty(A{i}), continue; end
    B(i,1:numel(A{i})) = num2cell(A{i});
end

所以我把第一个单元格数组作为：

>> celldisp(A)
A{1} =
    0.2217    0.1174    0.2967    0.3188
A{2} =
    0.5079    0.0855
A{3} =
    0.8010
A{4} =
     []
A{5} =
    0.7303    0.4886    0.5785    0.2373    0.4588
A{6} =
    0.5468    0.5211    0.2316    0.4889    0.6241
A{7} =
    0.3955    0.3674    0.9880    0.0377
A{8} =
    0.9133    0.7962    0.0987    0.2619    0.3354
A{9} =
    0.1366    0.7212    0.1068    0.6538
A{10} =
    0.7791    0.7150

变成了：

>> B
B = 
    [0.2217]    [0.1174]    [0.2967]    [0.3188]          []
    [0.5079]    [0.0855]          []          []          []
    [0.8010]          []          []          []          []
          []          []          []          []          []
    [0.7303]    [0.4886]    [0.5785]    [0.2373]    [0.4588]
    [0.5468]    [0.5211]    [0.2316]    [0.4889]    [0.6241]
    [0.3955]    [0.3674]    [0.9880]    [0.0377]          []
    [0.9133]    [0.7962]    [0.0987]    [0.2619]    [0.3354]
    [0.1366]    [0.7212]    [0.1068]    [0.6538]          []
    [0.7791]    [0.7150]          []          []          []

我们将元素作为2D单元格数组访问：

>> B{5,3}
ans =
    0.5785

编辑：

这是一个稍微不同的实现：

len = cellfun(@numel, A);
padding = arrayfun(@(n)cell(1,n), max(len)-len, 'UniformOutput',false);
B = cellfun(@num2cell, A, 'UniformOutput',false);
B = cellfun(@(b,pad) [b{:} pad], B, padding, 'UniformOutput',false);
B = cat(1, B{:});

EDIT2：

请注意，上述内容将返回2D 单元格数组。这是因为常规数字矩阵不能被锯齿（所有行必须具有相同的长度）。

如果您想获得2D 数字矩阵，则必须插入NaN值作为填充符：

C = B;
C(cellfun(@isempty,C))= {NaN};
C = cell2mat(C)

输出：

>> C
C =
    0.2217    0.1174    0.2967    0.3188       NaN
    0.5079    0.0855       NaN       NaN       NaN
    0.8010       NaN       NaN       NaN       NaN
       NaN       NaN       NaN       NaN       NaN
    0.7303    0.4886    0.5785    0.2373    0.4588
    0.5468    0.5211    0.2316    0.4889    0.6241
    0.3955    0.3674    0.9880    0.0377       NaN
    0.9133    0.7962    0.0987    0.2619    0.3354
    0.1366    0.7212    0.1068    0.6538       NaN
    0.7791    0.7150       NaN       NaN       NaN

更改单元格数组Matlab的格式

1 个答案:

编辑：

EDIT2：