Django:将模板值发布到视图

时间:2013-08-26 00:01:25

标签: python html django

问题:

我想发布到视图并使用隐藏值字段和提交按钮从模板传递值。提交按钮(即csrf_token)中的值通过,但隐藏值不通过。我从Wezkrug调试器检查request.POST只包含表单值,而不是隐藏字段中的'id'值。

背景

该按钮将您带到可以输入注释的表单。我正在尝试包含用户正在评论的review.id,以便轻松进行评论。我有'测试'的价值不是为了测试目的。

我的表格:

<div>
     <form method='POST' action='/add_comment/'>
         {% csrf_token %}
         <input type="hidden" name='id' value='test'>
         <input type="submit" value="Make a Comment">
     </form>
</div>

评论观点:

@login_required
def make_comment(request):
    if request.method == 'POST':

        form = CommentForm(request.POST)
        if form.is_valid():
            comment = form.save(commit=False)
            comment.user = request.user
            comment.save()
            # render?
            return HttpResponseRedirect('/results/', {
                'restaurant': get_object_or_404(
                                                Restaurant, 
                                                name=request.POST['name'], 
                                                address=request.POST['address']
                                                )
                })
    else:
        form = CommentForm()
    return render(request, 'stamped/comment.html', {'form': form})

评论模型:

class Comment(models.Model):
    content = models.TextField()
    review = models.ForeignKey(Review)
    user = models.ForeignKey(User)
    date_added = models.DateTimeField(auto_now_add=True)

评论ModelForm代码:

class CommentForm(ModelForm):
    class Meta:
        model = Comment
        exclude = ('user', 'review',)

我一直在尝试遵循这个问题中的策略,但是使用request.session dict是不可取的,因为Id必须为每次评论存储一个id,无论它们是否被评论过。

What is a more efficient way to pass variables from Template to View in Django?

有关如何在POST中包含隐藏值的任何想法?谢谢!

2 个答案:

答案 0 :(得分:8)

views.py

def make_comment(request):
    if request.method == 'POST':
        if 'prepair_comment' in request.POST:
            review = get_object_or_404(Review, pk=request.POST.get('id'))
            form = CommentForm({'review': review.id})
            return render(request, 'stamped/comment.html', {
                'form': form,
                })
        else: # save the comment

models.py

class CommentForm(ModelForm):
        class Meta:
               model = Comment
               exclude = ('user',)
               widgets = {'review': forms.HiddenInput()}

restaurant.html

<form method='POST' action='/add_comment/'>
    {% csrf_token %}
    <input type='hidden' value='{{ r.id }}' name='id'>
    <input type="submit" name='prepair_comment' value="Make a Comment">
</form>

答案 1 :(得分:0)

您可以使用form.cleaned_data访问表单。您也可以使用if form.is_valid(),或者如果您想在没有注释时忽略隐藏的测试值,那么您可以使用if / else逻辑来忽略隐藏值if comment is None:逻辑。

要访问表单并仅在注释不是None时记录测试值,views.py可能如下所示:

 def form_view(request):
      if request.method == 'POST'
        form = form(request.POST)
        if form.is_valid():
          comment = form.cleaned_data['comment']
          # do something with other fields
          if comment is not None:
            id = form.cleaned_data['test']
            # do something with the hidden 'id' test value from the form
         return HttpResponseRedirect('/thanks/')
       else:
         form = form()
       return render(request, 'form.html', {'form': form})

以下是我将参考的Django文档:

https://docs.djangoproject.com/en/dev/topics/forms/