Question

我已经对StackOverflow上的几乎所有JSON httppost教程和问题进行了整理，并认为我可能会发疯。有一次，在提交JSONObject并接收JSONObject之后，我的Android应用程序完美地拉下数据并显示它。现在，在失去了一天的编码后，我无法让它重新开始工作。

我第一次使用this作为基础然后它起作用了，所以有人可以告诉我为什么我可能会在HttpClient.java中出现空错误吗？

更新：似乎现在正在工作，有点。但是收到的JSON应该看起来像this，而它包含的只是{“mainSearchResult”：[]}。想法？

注意：是的，我确实拥有所有导入功能，可以找到LogCat here。我只使用Java和Android进行了大约3周的编程，所以请尽可能简单地解释，希望不依赖其他StackOverflow帖子来解释它，因为我向你保证，我已经阅读过了。

public class HttpClient {

public static final String TAG = HttpClient.class.getSimpleName();

public static JSONObject SendHttpPost(String URL, JSONObject jsonObjSend) {

    try {
        DefaultHttpClient httpclient = new DefaultHttpClient();
        HttpPost httpPostRequest = new HttpPost(URL);

        StringEntity se = new StringEntity(jsonObjSend.toString());

        // Set HTTP parameters
        httpPostRequest.setEntity(se);
        httpPostRequest.setHeader("Accept", "application/json");
        httpPostRequest.setHeader("Content-type", "application/json");

        long t = System.currentTimeMillis();
        HttpResponse response = (HttpResponse) httpclient.execute(httpPostRequest);
        Log.i(TAG, "HTTPResponse received in [" + (System.currentTimeMillis()-t) + "ms]");

        // Get hold of the response entity (-> the data):
        HttpEntity entity = response.getEntity();

        if (entity != null) {
            // Read the content stream
            InputStream instream = entity.getContent();

            // convert content stream to a String
            String resultString= convertStreamToString(instream);
            instream.close();

            // Transform the String into a JSONObject
            JSONObject jsonObjRecv = new JSONObject(resultString);
            // Raw DEBUG output of our received JSON object:
            Log.i(TAG,"<JSONObject>\n"+jsonObjRecv.toString()+"\n</JSONObject>");

            return jsonObjRecv;
        } 

    }
    catch (Exception e)
    {
        // More about HTTP exception handling in another tutorial.
        // For now we just print the stack trace.
        e.printStackTrace();
    }
    return null;
}


private static String convertStreamToString(InputStream is) {
    /*
     * To convert the InputStream to String we use the BufferedReader.readLine()
     * method. We iterate until the BufferedReader return null which means
     * there's no more data to read. Each line will appended to a StringBuilder
     * and returned as String.
     * 
     * (c) public domain: http://senior.ceng.metu.edu.tr/2009/praeda/2009/01/11/a-simple-restful-client-at-android/
     */
    BufferedReader reader = new BufferedReader(new InputStreamReader(is));
    StringBuilder sb = new StringBuilder();

    String line = null;
    try {
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
    } catch (IOException e) {
        e.printStackTrace();
    } finally {
        try {
            is.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
    return sb.toString();
}

}

Answer 1

我使用不同的convertStreamToString方法：

 private static String convertStreamToString(InputStream is) {
        /*
         * To convert the InputStream to String we use the BufferedReader.readLine()
         * method. We iterate until the BufferedReader return null which means
         * there's no more data to read. Each line will appended to a StringBuilder
         * and returned as String.
         */
        BufferedReader reader = new BufferedReader(new InputStreamReader(is));
        StringBuilder sb = new StringBuilder();

        String line = null;
        try {
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            try {
                is.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
        return sb.toString();
    }

尝试打印响应后（这是在“Try Catch”范围内）：

String result= convertStreamToString(instream);
// now you have the string representation of the HTML request
instream.close();
Log.d("Reponse from request:",result); //Where you print to LogChat theresponse

然后我会尝试将String解析为JSONObject

JSONObject jObject = new JSONObject(result);             
   if(result!=null)
   {
    //Here is where you do your thing....
   }

Answer 2

May this help you.

 // Creating JSON Parser instance
        JSONParser jParser = new JSONParser();

        // getting JSON string from URL
        JSONObject json = jParser.getJSONFromUrl(url);
        JsonArray jsonArray=json.getJSONArray("mainSearchResult");
String strAudio=jsonArray.getJSONObject(0).getString("AudioStr");//move the loop towards it upto jsonArray.length() and get all the string in the same manner

  public JSONObject getJSONFromUrl(String url) {

        // Making HTTP request
        try {
            // defaultHttpClient
            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost(url);

            HttpResponse httpResponse = httpClient.execute(httpPost);
            HttpEntity httpEntity = httpResponse.getEntity();
            is = httpEntity.getContent();           

        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(
                    is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            is.close();
            json = sb.toString();
        } catch (Exception e) {
            Log.e("Buffer Error", "Error converting result " + e.toString());
        }

        // try parse the string to a JSON object
        try {
            jObj = new JSONObject(json);
        } catch (JSONException e) {
            Log.e("JSON Parser", "Error parsing data " + e.toString());
        }

        // return JSON String
        return jObj;

    }

Java SendHttpPost将返回null JSONObject

2 个答案: